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2 years ago

7

Mathematics

1 answer:

lara31 [8.8K]2 years ago

6 0

Answer:

The time spent by a physician with a patient

Step-by-step explanation:

Option C is the answer

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How to solve 10 (g+5)=2(g+9)

Ghella [55]

first multiply the outside numbers by both the numbers in the ()

10xg=10g 10x5=50 2xg=2g 2x9=18

then combine like terms

10g+50=2g+18

8g=32

then divide

g=4

4 0

3 years ago

PLS ANSWER QUICK! Thanks!

ziro4ka [17]

Answer:

The correct answer would be $a=\sqrt{c^2-b^2}$

Step-by-step explanation:

given $a^2+b^2=c^2$ we want to solve for a

How?

We can do this by using basic algebra ( isolating the variable (a ))

Step 1 subtract $b^2$ from each side

$a^2+b^2-b^2=a^2\\c^2-b^2=c^2-b^2$

now we have $a^2=c^2-b^2$

step 2 take the square root of each side

$\sqrt{a^2} =a\\\sqrt{c^2-b^2} =\sqrt{c^2-b^2}$

we're left with $a=\sqrt{c^2-b^2}$

Hence your answer is A

5 0

3 years ago

Which expression is equivalent??? help!

dexar [7]

Answer:

The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

Step-by-step explanation:

Given:

$\sqrt[3]{256x^{10}y^{7} }$

Solution:

We will see first what is Cube rooting.

$\sqrt[3]{x^{3}} = x$

Law of Indices

$(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}$

Now, applying above property we get

$\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})$