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3 years ago

Here another one Thanks

Mathematics

1 answer:

Luden [163]3 years ago

7 0

So in example 1 you need to round 73.2754 to the nearest whole number. Since the number in the tenths column is less than 5 the number is rounded down to 73. In example 2 you will need to round 276.72185 to the nearest whole. Since the number in the tenths column is 5 or above then you round the number up to 277. thats how u do what your trying to do [;

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What is 0.00277 scientific notation?

Harlamova29_29 [7]

2.77 × 10 ^ ( -3 ) is the answer

3 0

3 years ago

Read 2 more answers

What is the total number of digits used when the first 2002 positive even integers are written?

Luda [366]

The total number of digits used when the first 2002 positive even integers are written is 4 digits

<h3>How to find the number of sequence?</h3>

Using arithmetic sequence,

nth term = a + (n - 1)d

where

a = first term
d = common difference
n = number of terms

a = 2

d = 2

nth term = 2 + (2002 - 1)2

nth term = 2 + 4002

nth term = 4004

learn more on sequence here: brainly.com/question/15456604

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7 0

2 years ago

A recreation center charges nonmembers $3 to use the pool and $5 to use the basketball courts. A person pays $42 to use the recr

Andrei [34K]

Let x = times in the pool
Let y = times in the basketball courts

42=3x+5y
x+y=12
Therefore y = 12-x
Subsitute for y
42 = 3x + 5(12-x)
42 = 3x + 60 -5x
Subtract 60
-18 = -2x
9 = x

The person used the pool 9 times.

5 0

3 years ago

the hoover dam is 725 feet tall. how long would it take an object to fall from the top to the base of the dam? round the answer

Alinara [238K]

Answer:

45.05 seconds

Step-by-step explanation:

Use the formula: d = v $i$ t + $\frac{1}{2}$ a $t^{2}$

d = distance v $i$ = initial velocity (m/s)

t = time (s) a = acceleration (m/ $s^{2}$ )

m is meters and s is seconds. They are units of measurement so leave them be.

Assuming the object is simply dropped, the initial velocity is 0 since the object was not moving before it was dropped.

The distance is 725 feet, which is 220.98 meters.

The acceleration is 9.81m/ $s^{2}$ since that is the acceleration of Earth's gravity, aka free fall.

Time is what we are trying to find so just leave it as the variable t.

So plug the values into the equation:

220.98m = (0)(t) + $\frac{1}{2}$ (9.81m/ $s^{2}$ )(t)

220.98m = (4.905m/ $s^{2}$ )(t)

45.0519877676s = t

t = 45.05s

Remember to pay attention to units because your answer will be wrong otherwise

7 0

2 years ago

The scale on a map is 1: 75 000. (a) Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.

finlep [7]

Answer:

a. 1 200 000 km

b. 0.000 773 cm

c. 67 500 000 000 km²

d. 0.000 000 016 cm²

Step-by-step explanation:

a. Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.

Since the scale is 1 : 75000 that is 1 cm : 75000 km, we want to find the actual distance of 16 cm on the map. Let x be the actual distance in km.

So, 1 cm : 75000 km = 16 cm : x km

So, 1 cm/75000 km = 16 cm/x km

Thus x km = 16 cm × 75000 km/1 cm = 1 200 000 km

(b) Calculate length of a road on the map which is 0.58 km.

Let y be the length of road on the map. So, using our scale

1 cm : 75000 km = y cm : 0.58 km

So, 1 cm/75000 km = y cm/0.58 km

Thus y cm = 0.58 km × 1 cm/75000 km = 0.000 773 cm

(c) Calculate, in km², the ACTUAL area of a lake which is 12 cm2 on the map.

Since the scale is 1 : 75000 , the scale for the area would be the square of this. So, 1² : 75000² = 1 : 5 625 000 000 which is 1 cm² : 5 625 000 000 km²

Let z be the actual area of the lake.

So, 1 cm² : 5 625 000 000 km² = 12 cm² : z km²

So, 1 cm²/5 625 000 000 km² = 12 cm²/z km²

Thus z km² = 12 cm² × 5 625 000 000 km²/1 cm² = 67 500 000 000 km²

(d) Calculate the area of a play field on the map which has has an actual area of 90 km².

Let a represent the area of the play field on the map. Using our scale for the area,

1 cm² : 5 625 000 000 km² = a cm² : 90 km²

So, a cm² = 90 km² × 1/5 625 000 000 km² = 0.000 000 016 cm²

4 0

3 years ago