The subtraction of complex numbers
is cos(π)+i sin(π).
Given
[cos(3π/4+i sin(3π/4) and
=cos (π/2) +i sin(π/2)
We have to find the value of
.
A complex number is a number that includes real number as well as a imaginary unit in which
. It looks like a+ bi.
We have to first solve
and then we will be able to find the difference.

[ cos (3π/4)+i sin (3π/4)]
[cos(π-π/4)+ i sin (π-π/4)]
=
[-cos(π/4)+sin (π/4)]
=
(-1/
+1/
)
=
=0
cos(π/2)+i sin (π/2)
=0+i*1
=1
Now putting the values of
,

=-1
=-1+i*0
=cos (π)+i sin(π)
Hence the value of difference between
is cos(π)+i sin(π).
Learn more about complex numbers at brainly.com/question/10662770
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You’ve got the correct answer (which is the first one) hope this helps
Any number, either positive or negative raised to the power of 0 is equal to 1.
The answer is 2.6 m/s
The speed (v) is distance (d) through time (t).
v = d/t
We know:
d = 390 m
t = 150 s
v = d/t
v = 390 m / 150s
v = = 2.6 m/s