The angle of rotation of triangle ABC to A'B'C is 105°
<h3>How to illustrate the information?</h3>
It should be noted that the rotation from ABC to A'B'C is in a clockwise direction.
Point B is also on the x axis and point B' is in the second quadrant.
In this case, the angle that depicts the second quadrant is 105°.
In conclusion, the correct option is D.
The complete question is:
Triangle A’ B’ C’ is the image of A B C under a rotation about the origin, (0,0)
Determine the angle of rotation
A. -105 degrees
B. -75 degrees
C. 75 degrees
D. 105 degrees
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Answer:
Step-by-step explanation:
Dimensions: 1 x 1 x 36 or 12 x 3 x 1 or 9 x 4 x 1 or 9 x 2 x 2
He has 20 guppies?
This is what I got from the information. Unless they had eggs.
An arithmetic sequence starts with one number and you add the common difference to the previous term to get the current term
So...
f(x)=mx+b
m=common difference
b=starting point
f(11)=125=11m+b
-
f(1)=5=1m+b
--------
120=10m
Divide both sides by 10
12=m
Your common difference is 12.
Given,
3/3x + 1/(x + 4) = 10/7x
1/x + 1/(x+4) = 10/7x
Because the first term on LHS has 'x' in the denominator and the second term in the LHS has '(x + 4)' in the denominator. So to get a common denominator, multiply and divide the first term with '(x + 4)' and the second term with 'x' as shown below
{(1/x)(x + 4)/(x + 4)} + {(1/(x + 4))(x/x)} = 10/7x
{(1(x + 4))/(x(x + 4))} + {(1x)/(x(x + 4))} = 10/7x
Now the common denominator for both terms is (x(x + 4)); so combining the numerators, we get,
{1(x + 4) + 1x} / {x(x + 4)} = 10/7x
(x + 4 + 1x) / (x(x + 4)) = 10/7x
(2x + 4) / (x(x + 4)) = 10/7x
In order to have the same denominator for both LHS and RHS, multiply and divide the LHS by '7' and the RHS by '(x + 4)'
{(2x+4) / (x(x + 4))} (7 / 7) = (10 / 7x) {(x + 4) / (x + 4)}
(14x + 28) / (7x(x + 4)) = (10x + 40) / (7x(x + 4))
Now both LHS and RHS have the same denominator. These can be cancelled.
∴14x + 28 = 10x + 40
14x - 10x = 40 - 28
4x = 12
x = 12/4
∴x = 3
