Answer:
Step-by-step explanation:
To find : Acceleration in first 15 min . Distance between two cities Average speed of journey
Solution:
Each horizontal block is 1/8 hr = 7.5 min
Each vertical block is 10 km/hr
Time Velocity km/hr
0 Min ( 0 hr) 0
15 Min (1/4 hr) 50
45 Min (3/4 hr) 50
60 MIn ( 1 hr) 100
90 Min ( 3/2 hr) 100
120 Min ( 2hr) 0
Acceleration in first 15 min (1/4 hr) = (50 - 0)/(1/4 - 0) = 50/(1/4)
= 200 km/h²
Distance between two cities
= (1/2)(0 + 50)(1/4 - 0) + 50 * (3/4 - 1/4) + (1/2)(50 + 100)(1 - 3/4) + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)
= 25/4 + 25 + 75/4 + 50 + 25
= 125
Distance between two cities = 125 km
Average Speed of journey = 125/2 = 62.5 km/hr
Acceleration in first 15 min = 200 km/h²
Distance between two cities = 125 km
Average Speed of journey = 62.5 km/hr
Hope this helps..
Let's use the equation 5x - 20 = 10 as an example for this.
To work backwards from this, you would add the same amount to each side.
You want to isolate the 5x so that you can solve for x.
To do that, you would add 20.
But again, you must add and subtract the same amount to both sides.
So it would look a bit like this:
5x - 20 + 20 = 10 + 20
That would simplify to 5x = 30, or in other words, x = 6.
Basically, you isolate the multiple of the variable then divide the answer to the equation from that multiple.
In the example, 5 is the multiple and after isolating it, the answer was 30.
30 ÷ 5 = 6
x = 6
Hope this helps :)
Answer:
WHAT ON EARTH
Step-by-step explanation:
I believed it’s the second one.
