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Darya [45]
3 years ago
14

Select the correct answer.

Mathematics
1 answer:
Setler79 [48]3 years ago
3 0

Answer:

A. 2·x² + 16·x + 32 ≥ 254

Step-by-step explanation:

The given dimensional relationship between the dimensions of the photo in the center of the cake and the dimensions of the cake are

The width of the cake = The width of the photo at the center of the cake, x + 4 inches

The length of the cake = 2 × The width of the cake

The area of the cake Wanda is working on ≥ 254 in.²

Where 'x' represents the width of the photo (at the center of the cake), let 'W' represent the width of the cake, let 'L' represent the length of the cake, we get;

W = x + 4

L = 2 × W

Area of the cake, A = W × L ≥ 254

∴ A = (x + 4) × 2 × (x + 4) = 2·x² + 16·x + 32 ≥ 254

The inequality representing the solution is therefore;

2·x² + 16·x + 32 ≥ 254

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4 0
2 years ago
-2 4/5 + 1/4 equals what ?
vlada-n [284]
Hey there! :)

Since 2 4/5 is greater than 1/4, the answer is negative.

You can just subtract 2 4/5 and 1/4 and add the (-) sign

2 4/5 - 1/4

Change the fractions so they can have a common denominator: 20

2 4/5 = 2 16/20

1/4 = 5/20

2 16/20 - 5/20 = 2 11/20

Add the (-) sign → -2 11/20

Answer ⇒ -2 11/20

:)
5 0
3 years ago
What is the vertex of the function?
egoroff_w [7]
<h2>Explanation:</h2><h2></h2>

Here you haven't provided any function, so I'll assume this one:

f(x)=3x^2-18x+33

This is a quadratic function whose graph represents a parabola. Any parabola has its vertex at the point:

V(x,y) \\ \\ \\ x=-\frac{b}{2a} \\ \\ y=f(-\frac{b}{2a}) \\ \\ \\ where: \\ \\ \\ f(x)=ax^2+bx+c \\ \\ \\ So: \\ \\ a=3 \\ \\ b=-18 \\ \\ c=33

Therefore:

x=-\frac{(-18)}{2(3)}=3 \\ \\ f(3)=3(3)^2-18(3)+33=27-54+33=6

Therefore, the vertex is:

\boxed{V(3,6)}

6 0
3 years ago
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