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3 years ago

30 points!!! I think. Anyways, what’s your favorite thing to do with your mom.

2 answers:

4 0

My mom is rly toxic and doesn’t have a relationship w me anymore but I used to like to go shopping w her at the mall and we would get lunch and have a good time.

goldenfox [79]3 years ago

4 0

Answer: My favorite thing to do with my mom is either go shopping with her or cooking yummy desserts, like cookies, brownies, Etc...

The downside is that my mom get's really annoyed with me so i don't really go shopping especially with all this Coronavirus stuff going on.... And also what's your favorite thing to do with your mom???

Thank you so much!!! :D Stay safe and have a great day/night!!! :D

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Backgammon is a board game for two players in which the playing pieces are moved according to the roll of two dice. players win

Ivahew [28]

The rolls of the dice are independent, i.e. the outcome of the second die doesn't depend in any way on the outcome of the first die.

In cases like this, the probability of two events happening one after the other is the multiplication of the probabilities of the two events.

So, the probability of rolling two 6s is the multiplication of the probabilities of rolling a six with the first die, and another six with the second:

$P(\text{rolling two 6s}) = P(\text{rolling a 6}) \cdot P(\text{rolling a 6}) = \dfrac{1}{6} \cdot \dfrac{1}{6} = \dfrac{1}{36}$

Similarly,

$P(\text{rolling two 3s}) = P(\text{rolling a 3}) \cdot P(\text{rolling a 3}) = \dfrac{1}{6} \cdot \dfrac{1}{6} = \dfrac{1}{36}$

Actually, you can see that the probability of rolling any ordered couple is always 1/36, since the probability of rolling any number on both dice is 1/6:

$P(\text{rolling any ordered couple}) = P(\text{rolling the first number}) \cdot P(\text{rolling the second number}) = \dfrac{1}{6} \cdot \dfrac{1}{6} = \dfrac{1}{36}$

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3 years ago

Norio, Gayle, and Tonya are playing a card game. They have a stack of red cards, a stack of yellow cards, and a stack of green c

Montano1993 [528]

Answer:

Step-by-step explanation

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3 years ago

Simultaneous equations 2x+3y=13 4x-y=-2

Rufina [12.5K]

Answer:

(0.5, 4 )

Step-by-step explanation:

Given the 2 equations

2x + 3y = 13 → (1)

4x - y = - 2 → (2)

Multiplying (2) by 3 and adding to (1) will eliminate the term in y

12x - 3y = - 6 → (3)

Add (1) and (3) term by term to eliminate y

14x = 7 ( divide both sides by 14 )

x = 0.5

Substitute x = 0.5 into either of the 2 equations and evaluate for y

Substituting into (1)

2(0.5) + 3y = 13

1 + 3y = 13 ( subtract 1 from both sides )

3y = 12 ( divide both sides by 3 )

y = 4

Solution is (0.5, 4 )

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4 years ago

Manuel ate 1/3 of the cracker on a plate. His brother ate 1/4 of the cracker. their were 5 crackers left on the plate. How many

Lynna [10]

5 and 7/12 of a cracker

6 0

3 years ago

Read 2 more answers

How do you find a missing number in a multiplication equation?

Slav-nsk [51]

If it gives you your total, and another number, divide the 2

example:

25 • x = 75

75/25= 3

x=3

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3 years ago