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ella [17]
3 years ago
5

I know its a lot but pls help its due soon

Mathematics
1 answer:
alex41 [277]3 years ago
7 0

Answer:

<em>6</em>.

a) where +3b should be - 3b.

b) -4(5a+2-3b)

c) -4(5a+2-3b)= -20a-8+12b

<em>11</em><em>.</em><em> </em>

-6(x-3)

<em>12</em><em>.</em>

-15y-40= -5(3y+8)

-5(3y+8)= -15y-40

<em>I</em><em> </em><em>really</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>,</em><em> </em><em>good</em><em> </em><em>luck</em><em>!</em><em> </em><em>:</em><em>)</em><em> </em>

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Consider this system of linear equations: y=4/5x-3 y=4/5×+1 a. Without graphing, determine how many solutions you would expect t
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The solution of a system of linear equations is the point where the two lines meet. Note that for the given equations, both lines have the same slope (4/5). If two lines have the same slope, it means that those lines are parallel. Parallel lines do not meet at any point, they stay parallel to the infinite.

Therefore, since this two lines are parallel, they don't meet and the system has no solution.

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1 year ago
A painting company will paint this wall of a building. The owner gives him the following dimensions.
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The given area of the 52\frac{1}{2} ft. by 33 ft. wall less the areas of the Windows and the Door give the area of the painted part of the wall as  \underline{1642\frac{9}{16}} ft.²

<h3>How can the area of the painted part be calculated?</h3>

The area of the painted part of the wall is \underline{1642\frac{9}{16}} ft.²

The given dimensions of the wall are;

The width of the wall = 52\frac{1}{2} ft.

The height of the wall = 33 ft.

The painted area = Area of the wall - (Area of the widows + The door)

Which gives;

52\frac{1}{2} \times 33 - \left(6\frac{1}{4} \times 5\frac{3}{4} + 3\frac{1}{8} \times 4 + 9\frac{1}{2}  + 4 \times 8 \right) = \mathbf{ 1642 \frac{9}{16}}

The area of the painted part of the wall is \underline{1642\frac{9}{16}} ft.²

Learn more about the area of a rectangle here:

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3 years ago
Two jets leave an air base at the same time and travel in opposite directions. One jet travels 80 mi/h faster than the other. If
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Jet 1 moves with a speed of  672 mi/h, while jet 2 moves with a speed of  672 mi/h + 80mi = 752 mi/h.

<h3>How to get the rate of each jet?</h3>

Let's say that the rate (or speed) of the slower jet is R, then the rate of the faster jet is:

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Now, if we step on any of the two jets (such that we view it as if it doesn't move) the other jet will move with a speed equal to:

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We know that after 8 hours, the to jets are 11,392 mi apart, then we know that:

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Now we can solve that for R:

2*R + 80mi/h = 11,392 mi/8h = 1,424 mi/h

R = 1,424 mi/h - 80mi/h)/2 = 672 mi/h

So Jet 1 moves with a speed of  672 mi/h, while jet 2 moves with a speed of  672 mi/h + 80mi = 752 mi/h.

If you want to learn more about speed:

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2 years ago
Which equation is represented by the intersection of the graphs below?
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Answer:

it is d

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