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3 years ago

6

Pls help me I am confused

2 answers:

Maslowich3 years ago

8 0

Answer:

$\huge\boxed{A.\ \dfrac{565}{182}}$

Step-by-step explanation:

$\dfrac{8}{7}-(5x-3)=\dfrac{1}{5}x-12\\\\\dfrac{8}{7}-5x+3=\dfrac{1}{5}x-12\qquad|\text{multiply both sides by 35}\\\\35\cdot\dfrac{8}{7}-35\cdot5x+35\cdot3=35\cdot\dfrac{1}{5}x-35\cdot12\qquad|\text{simplify}\\\\5\cdot8-175x+105=7\cdot x-420\\\\40-175x+105=7x-420\\\\-175x+(40+105)=7x-420\\\\-175x+145=7x-420\qquad|\text{subtract 145 from both sides}\\\\-175x=7x-565\qquad|\text{subtract }7x\ \text{from both sides}\\\\-182x=-565\qquad|\text{divide both sides by (-182)}\\\\x=\dfrac{565}{182}$

Vsevolod [243]3 years ago

3 0

Answer:

A

Step-by-step explanation:

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Answer:

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<u>Pre-Algebra</u>

Order of Operations: BPEMDAS
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Step-by-step explanation:

<u>Step 1: Define</u>

Slope <em>m</em> = 3/7

Point (14, 0)

<u>Step 2: Find y-intercept </u><em><u>b</u></em>

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3 years ago

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Read 2 more answers

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Ilia_Sergeevich [38]

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A. Area of a circle is given by

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So to find the rate of the area:

$\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}$

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$\frac{dr}{dt}=\frac{726}{(t+11)^{3}}$

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$\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}$

Multipying and simplifying:

$\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$

The rate at which the area is increasing is given by expression $A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}$ .

B. At t = 5, rate is:

$A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}$

$A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}$

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$A'(5)=1.76268$

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