Answer:
1/12
Step-by-step explanation:
There are two dices being rolled. A dice has six faces numbered from one to six. A fair dice means that the probability of each number to appear is equal. Thus the probability of any number showing up is:
P(a number appears on the dice) = how much times the number has been displayed on the dice/number of faces of the dice.
Since all numbers appear once, and there are six sides of a dice. therefore:
P(a number appears on the dice) = 1/6. Thus, P(6 appears on a dice) = 1/6.
As far as the odd numbers are concerned, there are three even numbers and three odd numbers on the dice. So P(odd number appears on the dice) = 3/6 = 1/2.
Assuming that the probabilities of both the dices are independent, we can safely multiply both the probabilities. Thus:
P(first dice lands on a 6 and second dice lands on an odd number) = 1/6 * 1/2 = 1/12.
Thus, the final probability is 1/12!!!
So of you set it equal to each other
150m+3m = 9m
-3m = -3m
you get 150m=6m
and you divide by 6 on each side so it comes out to 25 minutes... I think...
58 the 5 is 50 and the 8 is just 8 . the 5 is in the 50s place and the 8 is in the ones place
2%(random sentence bc I need 20 characters)
