What is the center of the circle that has a diameter whose endpoints are (2, 7) and (-6, -1)?

Solve In 2x + In 2=0

irakobra [83]

Solving $ln(2x)+ln(2)=0$ we get, $x=\frac{1}{4}$

Step-by-step explanation:

We need to solve: $ln(2x)+ln(2)=0$

Solving:

$ln(2x)+ln(2)=0$

Adding -ln(2) on both sides:

$ln(2x)+ln(2)-ln(2)=0-ln(2)$

$ln(2x)=-ln(2)$

Using logarithmic rule: if $log_a b =c\,\,then\,\, b=a^c$

So,

$2x=e^{-ln(2)}$

Simplifying:

$2x=(e^{ln(2)})^{-1}\\e^{ln(2)}=2\\2x=(2)^{-1}\\2x=\frac{1}{2} \\x=\frac{1}{2x2}\\x=\frac{1}{4}$

So, Solving $ln(2x)+ln(2)=0$ we get, $x=\frac{1}{4}$

Keywords: Logarithms

Learn more about Logarithms at:

#learnwithBrainly

4 0

3 years ago

Solve for x Urgent need help

fiasKO [112]

I believe you need to solve this using the quadratic formula!
To begin, this is what it is:
x= -b ± √ b^2 - 4ac / 2a
Just plug in what you have in your problem...
2 being a, 13 being b, and -24 being c.
So we get:
x= -13 ± √13^2 - 4(2)(-24) / 2(2)
x= -13 ± √169 - 8 (-24) / 4
x= -13 ± √169 + 192 / 4
x= -13 ± √361 / 4
The square root of 361 is 19.
So you have: -13 ± 19 / 4.
Here's where you take the equation -13 ± 19 and put the addition and subtraction sign to use.
-13 - 19 = -32
and
-13 + 19 = 6
Now all is left to do is divide the two numbers by 4.
-32/4 = -8
and
6/4 = 3/2

x = -8, 3/2

6 0

3 years ago

The picture shows a barn door:

Hitman42 [59]

Answer:

(D)9 divided by sin 60 degrees

Step-by-step explanation:

From the given figure, using trigonometry

$\frac{BC}{AB}=sin60^{{\circ}}$