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yaroslaw [1]
3 years ago
5

Solve for EG. A) 18 B) 12 9 D) 6​

Mathematics
1 answer:
Galina-37 [17]3 years ago
8 0

Answer:

It's be 9. The opposing line is 8, and because it's slightly offset, I'd wager it's 9.

Let me know if you need more help! :)

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REY [17]
From what I got there is one real solution :)

Rearrange the second equation to give y=2-2x, substitute into the first equation to give you a value for x and then using that you can work out y for the exact coordinates of intersection :)

Also they are both straight line graphs so they will either have one or no solutions

Hope this helped :)
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3 years ago
The figure shown is a rectangle. The green shape in the figure is a square. The blue and white shapes are rectangles, and the ar
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3 0
3 years ago
What is the approximate value of 113−−−√ to the nearest tenth?
castortr0y [4]

Answer:

10.6

Step-by-step explanation:

1. First, we need to find which digits √(113) is between, and that would be 10 and 11.

2. Okay, so √(113) is between 10 and 11, meaning 113 is between 100 and 121.

3. Since 113 is a little over half between 100 and 121, let's multiply 10.6 by 10.6 to see how close we are to 113:

  • 10.6 * 10.6
  • 112.36

4. 112.36 is pretty close to 113, therefore, the dot on the number-line should be placed at 10.6.

7 0
3 years ago
A 2003 study of dreaming found that out of a random sample of 106 ​people, 80 reported dreaming in color.​ However, the rate of
Vlad [161]

Answer:

Step-by-step explanation:

Hello!

You have the following experiment, a random sample of 106 people was made and they were asked if they dreamed in color. 80 persons of the sample reported dreaming in color.

The historical data from the 1940s informs that the population proportion of people that dreams in color is 0.21(usually when historical data is given unless said otherwise, is considered population information)

Your study variable is a discrete variable, you can define as:

X: Amount of people that reported dreaming in colors in a sample of 106.

Binomial criteria:

1. The number of observation of the trial is fixed (In this case n = 106)

2. Each observation in the trial is independent, this means that none of the trials will have an effect on the probability of the next trial (In this case, the fact that one person dreams in color doesn't affect or modify the probability of the next one dreaming in color)

3. The probability of success in the same from one trial to another (Or success is dreaming in color and the probability is 0.21)

So X~Bi(n;ρ)

In order to be able to run a proportion Z-test you have to apply the Central Limit Theorem to approximate the distribution of the sample proportion to normal:

^ρ ≈ N(ρ; (ρ(1-ρ))/n)

With this approximation, you can use the Z-test to run the hypothesis.

Now what the investigators want to know is if the proportion of people that dreams in color has change since the 1940s, so the hypothesis is:

H₀: ρ = 0.21

H₁: ρ ≠ 0.21

α: 0.10

The test is two-tailed,

Left critical value: Z_{\alpha/2} = Z_{0.95} = -1.64

Right critical value: Z_{1-\alpha /2} = Z_{0.95} = 1.64

If the calculated Z-value ≤ -1.64 or ≥ 1.64, the decision is to reject the null hypothesis.

If -1.64 < Z-value < 1.64, then you do not reject the null hypothesis.

The sample proportion is ^ρ= x/n = 80/106 = 0.75

Z= <u>     0.75 - 0.21    </u> = 12.83

    √[(0.75*0.25)/106]

⇒Decision: Reject the null hypothesis.

p-value < 0.00001 is less than 0.10

If you were to conduct a one-tailed upper test (H₀: ρ = 0.21 vs H₁: ρ > 0.21) with the information of this sample, at the same level 10%, the critical value would be Z_{0.90}1.28 against the 12.83 from the Z-value, the decision would be to reject the null hypothesis (meaning that the proportion of people that dreams in colors has increased.)

I hope this helps!

4 0
3 years ago
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