Let x be the number of hours ling work on monday.
We know that she worked three more hours on tuesday that in monday, this can be express as :
We also know that in wednesday she worked on more hour than twice the number on mondays, this can be expressed as:
The total number of hours she worked this three days in two more than five the number of hours she worked on monday, this can be express as :
Now , once we have all the expressions we add the expressions of the days and equate them to the total
Now we solve the equation
Therefore , she worked 2 hours on monday.
PLEASE MARK ME AS BRAINLIEST
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
</span>
<span>I hope this helps! </span>
X-3=-6
if you take away 3 from a number, you will get -6
x=-3
Answer:
89:120
Step-by-step explanation:
convert the both times to minutes
2 hours is 120 mins
89:120
both divisible by 1
89:120
it cant be simplified further
