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3 years ago

13

A line passes through the point (4,-4) and has a slope of 5/4.

1 answer:

tester [92]3 years ago

6 0

Answer:

y = 5/4x - 9

Step-by-step explanation:

y = mx + b

when you plot 4, -4 you have your first clue and point. then go up 5 and right 4 or down5 and left 4. When you go down you will reach the y intercept. On the number- 9. So -9 is your y intercept which goes in b.

Since 5/4 goes in the mx since it is slope the answer is y = 5/4 - 9

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Factor this expression:<br><br> mn - 4m - 5n + 20

andrey2020 [161]

Answer:

(m-5) (n-4)

Step-by-step explanation:

mn - 4m - 5n + 20

We will factor by grouping

mn -5n -4m +20

Factor an n out of the first 2 terms and a -4 out of the last 2 terms

n (m-5) -4(m-5)

Now factor out a m-5

(m-5) (n-4)

6 0

3 years ago

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago

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Vlad [161]

Answer: 1/4

Step-by-step explanation:

The cheesiest recipe would be 1 cup and the least cheesy recipe would be 3/4 cups

1 - 3/4 = 1/4

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ICE Princess25 [194]

Answer:

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Step-by-step explanation:

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3 years ago

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kozerog [31]

Answer: $37.20

Step-by-step explanation:

Just add those 2 amounts together

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3 years ago

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