Please help i’m so confused LMC of 9, 12 and 24

Mathematics

2 answers:

julia-pushkina [17]2 years ago

7 0

Answer:

The LCM of 9, 12, and 24, is 72. 

Step-by-step explanation:

To find the answer you must figure out the factors of each number, and see which factor has the same number.

Factors of 9:  Factors of 12: Factors of 24: 

9 12 24

18 24 48

27 36 72

36 48

45 60

54 72

63

72

When we look at all these factors, none of them have the same number except 72. Since all of these factors have 72 in them, this is the LCM of 9, 12, and 24.

Leya [2.2K]2 years ago

5 0

Answer:

Step-by-step explanation:

9x8 = 72

12x6=72

24x3=72

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2 years ago

Find maclaurin series

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Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$