The answer would be 61m^2
5x11=55
8-5=3
11-9=2
2x3=6
6+55=61
and since it is the area it is squared
hope this helps
Answer:
26.8
Step-by-step explanation:
Because 33.5 was the average of how many students were in a classroom (if there were 4 classrooms), then 33.5 is can somewhat be the average of how many students were in one classroom; 1/4 of the classrooms can hold an average of 33.5.
Total students that were divided into 4 classrooms :
33.5 × 4 = 134
So if there is 134 students that will be grouped into 5 different classrooms, divide 134 by 5 to find the average amount of students that will be grouped.
134 ÷ 5 = 26.8
So, the average amount of students that will be grouped if they were divided into 5 classrooms would be 26.8 .
Hope this helped !
∠ACB is an inscribed angle, so
m∠ACB= (1/2)mAB =(1/2)*50=25⁰
m∠ACB= 25⁰
Answer:
D.
Step-by-step explanation:
Sorry yo i just need points :/
