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2 years ago

H(x)= ⎩ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎧ 8+6x x+4 10 4x−3 , , , x<−7 −7≤x<−5 x≥−5

Mathematics

1 answer:

motikmotik2 years ago

4 0

Answer:

$h(-6) = -\frac{1}{5}$

Step-by-step explanation:

Given

$h(x) =\left[\begin{array}{cc}8 + 6x\ \ &x < -7\\\frac{x + 4}{10} &-7 \le x$

Required

Determine h(-6)

To do this, we make use of:

$h(x) = \frac{x + 4}{10}$

Because $-7 \le -6$

So, we have:

$h(x) = \frac{x + 4}{10}$

$h(-6) = \frac{-6 + 4}{10}$

$h(-6) = \frac{-2}{10}$

Simplify

$h(-6) = -\frac{1}{5}$

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2 years ago

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Step-by-step explanation:

Your question is incomplete without an attachment (See attachment)

Required

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2 years ago

H(x)= ⎩ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎧ ​ 8+6x x+4 10 ​ 4x−3 ​ , , , ​ x<−7 −7≤x<−5 x≥−5 ​

H(x)= ⎩ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎧ 8+6x x+4 10 4x−3 , , , x<−7 −7≤x<−5 x≥−5