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Ymorist [56]
3 years ago
11

H(x)= ⎩ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎧ ​ 8+6x x+4 10 ​ 4x−3 ​ , , , ​ x<−7 −7≤x<−5 x≥−5 ​

Mathematics
1 answer:
motikmotik3 years ago
4 0

Answer:

h(-6) = -\frac{1}{5}

Step-by-step explanation:

Given

h(x) =\left[\begin{array}{cc}8 + 6x\ \ &x < -7\\\frac{x + 4}{10} &-7 \le x

Required

Determine h(-6)

To do this, we make use of:

h(x) = \frac{x + 4}{10}

Because -7 \le -6

So, we have:

h(x) = \frac{x + 4}{10}

h(-6) = \frac{-6 + 4}{10}

h(-6) = \frac{-2}{10}

Simplify

h(-6) = -\frac{1}{5}

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