Answer:
an immediate.
Explanation:
It is because of the instruction encoding and decoding.Intel which make these instructions decided not include instructions which provide no real advantage. MOV segment register is one of them because segment register need not to be changed very often.This saves the space in instruction encoding.
Answer:
def first_a(n):
lst1 =[x for x in range(1,n+1)if x%6==0 or x%11 ==0]
print(lst1)
Explanation:
Above is a function in python programming language. We have used list comprehension to check numbers that are multiples of 6 or 11 in a range.
When this function is called it will receive an argument (n) of type integer, a range will then be generated from 1 to n+1 since n is inclusive. The modulo operator is used to determine is a value is a multiple of 6 or 11, since their multiples will evaluate to 0
Answer:

Explanation:
The statements are logically equivalent if they have the same truth tables. So let´s use truth tables in order to determine if they are logically equivalent or not:
The picture that I attached you shows the truth table for each case. As you can see in the highlight columns:

They are logically equivalent because they have exactly the same truth values between each other. Hence, we can conclude that they are logically equivalent.
Answer:
// here is code in C++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int x=5,y=2,z=9;
int min;
// find the smallest value and assign to min
// if x is smallest
if(x < y && x < z)
// assign x to min
min=x;
// if y is smallest
else if(y < z)
// assign y to min
min=y;
// if z is smallest
else
// assign z to min
min=z;
// print the smallest
cout<<"smallest value is:"<<min<<endl;
return 0;
}
Explanation:
Declare and initialize variables x=5,y=2 and z=9.Then check if x is less than y and x is less than z, assign value of x to variable "min" .Else if value of y is less than value of z then smallest value is y, assign value of y to "min".Else z will be the smallest value, assign its value to "min".
Output:
smallest value is:2