Answer:
9/20
Step-by-step explanation:
n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
Answer:
D. 16
Step-by-step explanation:
Do the division first
-16 ÷ (-4) = 4 then do the sum
12 + 4 = 16
Answer:
The first 2 and the last one
Step-by-step explanation:
You need to have an input per output, and to choose one or multiple the need to have a continuous pattern. Ex.+5 ad -2 on both sides every time would be a linear function.
