Check the picture below, so the green line is really the radius of the circle, and we know its center.
![~~~~~~~~~~~~\textit{distance between 2 points}\\\\(\stackrel{x_1}{0}~,~\stackrel{y_1}{-3})\qquad(\stackrel{x_2}{\frac{15}{2}}~,~\stackrel{y_2}{1})\qquad \qquadd = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}\\\\\\\stackrel{radius}{r}=\sqrt{[\frac{15}{2} - 0]^2 + [1 - (-3)]^2}\implies r=\sqrt{\left( \frac{15}{2} \right)^2 + (1+3)^2}\\\\\\r=\sqrt{\left( \frac{15}{2} \right)^2 +4^2}\implies r=\sqrt{\frac{225}{4} + 16}\implies r=\sqrt{\cfrac{289}{4}}\implies r=\cfrac{17}{2}\\\\[-0.35em]\rule{34em}{0.25pt}](https://tex.z-dn.net/?f=~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%5C%5C%28%5Cstackrel%7Bx_1%7D%7B0%7D~%2C~%5Cstackrel%7By_1%7D%7B-3%7D%29%5Cqquad%28%5Cstackrel%7Bx_2%7D%7B%5Cfrac%7B15%7D%7B2%7D%7D~%2C~%5Cstackrel%7By_2%7D%7B1%7D%29%5Cqquad%20%5Cqquadd%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%5C%5C%5C%5C%5C%5C%5Cstackrel%7Bradius%7D%7Br%7D%3D%5Csqrt%7B%5B%5Cfrac%7B15%7D%7B2%7D%20-%200%5D%5E2%20%2B%20%5B1%20-%20%28-3%29%5D%5E2%7D%5Cimplies%20r%3D%5Csqrt%7B%5Cleft%28%20%5Cfrac%7B15%7D%7B2%7D%20%5Cright%29%5E2%20%2B%20%281%2B3%29%5E2%7D%5C%5C%5C%5C%5C%5Cr%3D%5Csqrt%7B%5Cleft%28%20%5Cfrac%7B15%7D%7B2%7D%20%5Cright%29%5E2%20%2B4%5E2%7D%5Cimplies%20r%3D%5Csqrt%7B%5Cfrac%7B225%7D%7B4%7D%20%2B%2016%7D%5Cimplies%20r%3D%5Csqrt%7B%5Ccfrac%7B289%7D%7B4%7D%7D%5Cimplies%20r%3D%5Ccfrac%7B17%7D%7B2%7D%5C%5C%5C%5C%5B-0.35em%5D%5Crule%7B34em%7D%7B0.25pt%7D)
![\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{0}{ h},\stackrel{-3}{ k})\qquad \qquad radius=\stackrel{\frac{17}{2}}{ r} \\\\\\\ [x-0]^2~~ + ~~[y-(-3)]^2~~ = ~~\left( \cfrac{17}{2} \right)^2\implies x^2+(y+3)^2 = \cfrac{289}{4}](https://tex.z-dn.net/?f=%5Ctextit%7Bequation%20of%20a%20circle%7D%5C%5C%5C%5C%20%28x-%20h%29%5E2%2B%28y-%20k%29%5E2%3D%20r%5E2%20%5Cqquad%20center~~%28%5Cstackrel%7B0%7D%7B%20h%7D%2C%5Cstackrel%7B-3%7D%7B%20k%7D%29%5Cqquad%20%5Cqquad%20radius%3D%5Cstackrel%7B%5Cfrac%7B17%7D%7B2%7D%7D%7B%20r%7D%20%5C%5C%5C%5C%5C%5C%5C%20%5Bx-0%5D%5E2~~%20%2B%20~~%5By-%28-3%29%5D%5E2~~%20%3D%20~~%5Cleft%28%20%5Ccfrac%7B17%7D%7B2%7D%20%5Cright%29%5E2%5Cimplies%20x%5E2%2B%28y%2B3%29%5E2%20%3D%20%5Ccfrac%7B289%7D%7B4%7D)
First of all, recall that 1.5m is the same as 150cm.
Now, we simply build a proportion where we consider 48 to be 100, and wonder what 150 will be:
![48\div 100 = 150 \div x](https://tex.z-dn.net/?f=48%5Cdiv%20100%20%3D%20150%20%5Cdiv%20x)
Solving for x, we have
![x = \dfrac{150\cdot 100}{48}=\dfrac{15000}{48} = 312.5](https://tex.z-dn.net/?f=x%20%3D%20%5Cdfrac%7B150%5Ccdot%20100%7D%7B48%7D%3D%5Cdfrac%7B15000%7D%7B48%7D%20%3D%20312.5)
Which actually makes sense, because we're stating that 1.5m is about 300% of 48cm, which means three times as much. Which is true, because three times 48cm means 144cm, which is about 1.5m
Answer:
2
Step-by-step explanation:
Correct answer is 3: 8 (2x + 3y)
Answer: 84
Step-by-step explanation:
1) 294 ÷ 7 = 42
2) 42 × 2 = 84