All categories

3 years ago

PLSSS HELP PANICKING

Mathematics

1 answer:

devlian [24]3 years ago

8 0

Answer:

Step-by-step explanation:

a systems of equations can be made from the information on the problem

x+y=48

x=2y+3

since x= 2y+3 substitute 2y+3 in the firat equation to get:

(2y+3)+y=48 -> 3y+3=48 -> 3y=45 -> y=15

plug in 15 for y in the second equation to solve for x

x+15 =48 --> x=33

You might be interested in

a group raised $276 for its favorite charity. this is 23% of the amount it hopes to raise. how much money does the group want to

OverLord2011 [107]

Answer: The group wants to raise $1,200.

Step-by-step explanation:

We can use a proportion to solve.

part/whole = percent/100

If we insert the values:

276/x = 23/100

We can cross multiply.

276 x 100 = 27,600

27,600 / 23 = 1,200

$1,200 is the answer.

6 0

2 years ago

A submarine changes its position by −7 meters every second.

IgorLugansk [536]

The correct anwer is -21 and how i got that is by taking -7*300 to get -21 as my answer let me know if it helped any...

5 0

3 years ago

Read 2 more answers

I need Help!!!! Please Solve and show WORK!!!<br> 3(x+2)=15

ludmilkaskok [199]

Answer: x=3

Step-by-step explanation: First we do distributive property in the parentheses. Next we subtract both sides by 6. Lastly we divide both sides by 3. Algebraic Rules!!!

Work:

3(x+2)=15

3x+6=15

3x+6-6=15-6

3x=9

3x/3=9/3

x=3

4 0

3 years ago

Read 2 more answers

Could some please help me with this?

disa [49]

C: 20 m/s

Explanation:
Distance run: 1000m
Time passed: 50s
Distance divided by time equals speed.

1000m / 50s = 20 m/s

8 0

3 years ago

Read 2 more answers

PLEASE PLEASE ANSWER!

muminat

The area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

Solution:

Given radius = 4 cm

Diameter = 2 × 4 = 8 cm

Let us first find the area of the semi-circle.

Area of the semi-circle = $\frac{1}{2}\times \pi r^2$

$$=\frac{1}{2}\times \pi\times 4^2$

$$=\frac{1}{2}\times \pi\times 16$

Area of the semi-circle = $$8\pi$ cm²

Angle in a semi-circle is always 90º.

∠C = 90°

So, ABC is a right angled triangle.

Using Pythagoras theorem, we can find base of the triangle.

$AC^2+BC^2=AB^2$

$AC^2+4^2=8^2$

$AC^2=64-16$

$AC^2=48$

$AC=4\sqrt{3}$ cm

Base of the triangle ABC = $4\sqrt{3}$ cm

Height of the triangle = 4 cm

Area of the triangle ABC = $\frac{1}{2}\times b \times h$

$$=\frac{1}{2}\times 4\sqrt{3} \times 4$

Area of the triangle ABC = $8\sqrt{3}$ cm²

Area of the shaded region

= Area of the semi-circle – Area of the triangle ABC

= $$8\pi \ \text{cm}^2-8\sqrt{3}\ \text{cm}^2$

= $$8(\pi \ -\sqrt{3})\ \text{cm}^2$

Hence the area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

3 0

3 years ago