The amount of gas consumed by first and second car were 20 gallons and 15 gallons respectively.
<em><u>Explanation</u></em>
Suppose, 
gallons of gas were consumed by the first car.
As the total gas consumption in one week is 35 gallons, so the amount of gas consumed by second car will be: 
gallons.
The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a fuel efficiency of 15 miles per gallon of gas.
So, the <u>distance traveled by the first car</u> in gallons of gas 
miles and the <u>distance traveled by the second car</u> in gallons of gas 
miles.
Given that, the two cars went a <u>combined total of 925 miles</u>. So, the equation will be.....
So, the amount of gas consumed by the first car is 20 gallons and the amount of gas consumed by the second car is: (35 - 20) = 15 gallons.
The first term, a, is 2. The common ratio, r, is 4. Thus,
a_(n+1) = 2(4)^(n).
Check: What's the first term? Let n=1. Then we get 2(4)^1, or 8. Is that correct? No.
Try this instead:
a_(n) = a_0*4^(n-1). Is this correct? Seeking the first term (n=1), does this formula produce 2? 2*4^0 = 2*1 = 2. YES.
The desired explicit formula is a_(n) = a_0*4^(n-1), where n begins at 1.
Answer:
idk sorry
Step-by-step explanation:
Here's the way I see it: 5 cards are drawn, one by one, without replacement. Half (or 26) of the original deck are black and half (26) are white.
P(5 are not black) = P(5 are red)
P(5 are not black) = P(first card is red) * P(second card is red) * P(third card is red)*P(fourth card is red)*P(fifth card is red) =
(26/52) * (25/51) * (24/50) * (23/49) * (22/48) = 0.025 (answer)
We start with 52 cards. We draw one, leaving 51 cards, 25 of which are red. And so on.
