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natima [27]
3 years ago
7

Can someone answer these for me ? Because I don’t get it HA

Mathematics
1 answer:
Rzqust [24]3 years ago
6 0

first one

GH = KJ

or

KG = JH

second one

∆S = ∆U . So ∆U = 50°

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Dobby the house-elf has dropped all his socks on the floor in the middle of the night! He has 30 red socks, 22 gold socks and 14
Semenov [28]
Only 4 because the only way he cant get a pair is if he picks up a different colour to the previous sock, so by the fourth he will have picked up at two of at least one colour

3 0
3 years ago
What is x - the square root of -2
Lena [83]
Sqrt(-2), can be written as i * sqrt(2). Thus, our answer is x - i sqrt(2).
4 0
3 years ago
|1/2b-8|=|1/4b-1|<br> b=____ and ____
Deffense [45]

Answer:

  b = 12 and 28

Step-by-step explanation:

The absolute value equation |1/2b-8| = |1/4b-1| resolves to a piecewise linear function with three pieces. There are two solutions.

<h3>Domains</h3>

The absolute value function on the left has a turning point where its value is zero:

  1/2b -8 = 0

  b -16 = 0

  b = 16

The absolute value function on the right has a turning point where its value is zero:

  1/4b -1 = 0

  b -4 = 0

  b = 4

For b > 16, both absolute value functions are identity functions. In this domain, the equation is ...

  1/2b -8 = 1/4b -1

For 4 < b < 16, the function on the left negates its argument, so the equation in this domain is ...

  -(1/2b -8) = 1/4b -1

For b < 4, both functions negate their arguments, so the equation in this domain is ...

  -(1/2b -8) = -(1/4b -1)

For the purpose of finding the value of b, this is effectively identical to the equation for b > 16. (The value of b does not change if we multiply both sides of the equation by -1.)

<h3>Solutions</h3>

<u>Domain b < 4 ∪ 16 < b</u>

  1/2b -8 = 1/4b -1

  2b -32 = b -4 . . . . . . . . multiply by 4

  b = 28 . . . . . . . . . . . . add 32-b to both sides

This solution is in the domain of the equation, so is one of the solutions to the original equation.

<u>Domain 4 < b < 16</u>

  -(1/2b -8) = 1/4b -1 . . . . equation in this domain

  -2b +32 = b -4 . . . . . . multiply by 4

  36 = 3b . . . . . . . . . . . add 2b+4 to both sides

  12 = b . . . . . . . . . . . . divide by 3

This solution is in the domain of the equation, so is the other solution to the original equation.

<h3>Graph</h3>

For the purposes of the graph, we have define the function g(b) to be the difference of the two absolute value functions. The solutions are found where g(x) = 0, the x-intercepts. The graph shows those to be ...

  b = 12  and  b = 28

__

<em>Additional comment</em>

Defining g(b) = |1/2b-8| -|1/4b-1|, we can rewrite it as ...

  g(b)=\begin{cases}7-\dfrac{1}{4}b&\text{for }b < 4\\-\dfrac{3}{4}b+9&\text{for }4\le b < 16\\\dfrac{1}{4}b-7&\text{for }16\le b\end{cases}

Then the solutions are the values of b that make g(b) = 0.

4 0
2 years ago
4. Which of the following lines is perpendicular to y = -2X + 8?
Alenkinab [10]

For this case we have to by definition, if two lines are perpendicular then the product of its slopes is -1.

That is to say:

m_ {1} * m_ {2} = - 1

We have the following equation:

y = -2x + 8

So:

m_ {1} = - 2

Thus:

m_ {2} = \frac {-1} {m_ {1}}\\m_ {2} = \frac {-1} {- 2}\\m = \frac {1}{2}

Thus, a line perpendicular to the given line must have slope m = \frac {1} {2}.

Option A:

x + 2y = 8\\2y = -x + 8\\y = - \frac {1} {2} x + 4

It is not perpendicular!

Option B:

x-2y = 6\\2y = x-6\\y = \frac {1} {2} x-3

If it is perpendicular!

Option C:

2x + y = 4\\y = -2x + 4

It is not perpendicular!

Option D:

2x-y = 1\\y = 2x-1

It is not perpendicular!

The correct option is option B

ANswer:

Option B

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3 years ago
Quote: "The true art of memory is the art of attention"
Helen [10]

Answer:

What you remember is when someone gives you attention. You remember that because it makes you feel special.

Step-by-step explanation:

idk if this is right or not but this is what i think.

i cant get a whole paragraph out of this but here ya go (:

4 0
3 years ago
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