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2 years ago

Which of the following describes an element?

Physics

1 answer:

saw5 [17]2 years ago

7 0

Answer:

Matter made up of only one type of atom.

Explanation:

Please mark brainliest.

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Rick works off commission. He earns 10 percent of all manufacturing equipment he sells. if he made a sale of $9,000 how much was

Brut [27]

Answer:

$900

Explanation:

Step 1: Our output value is 9000.

Step 2: We represent the unknown value with x.

Step 3: From step 1 above,$9000=100\%$

Step 4: Similarly, x=10%

Step 5: This results in a pair of simple equations:

$9000=100

Step 6: By dividing equation 1 by equation 2 and noting that both the RHS (right hand side) of both

equations have the same unit (%); we have

\frac{9000}{x}=\frac{100\%}{10\%}

Step 7: Again, the reciprocal of both sides gives

\frac{x}{9000}=\frac{10}{100}$

\Rightarrow x=900$

Therefore, $10\%$ of $9000$ is $900$

3 0

2 years ago

Read 2 more answers

A 10000 kg rocket blasts off vertically from the launch pad with a constant upward of 2.25 m/s2 and feels no appreciable air res

Sloan [31]

Answer:

The maximum height that the rocket reaches is 645.5 m.

Explanation:

Given that,

Mass = 10000 kg

Acceleration = 2.25 m/s²

Distance = 525 m

We need to calculate the velocity

Using equation of motion

$v^2=u^2+2as$

Put the value in the equation

$v^2=0+2\time2.25\times525$

$v=\sqrt{2\times2.25\times525}$

$v=48.60\ m/s$

We need to calculate the maximum height with initial velocity

Using equation of motion

$v^2=u^2-2gh$

$h=\dfrac{v^2-u^2}{-2g}$

Put the value in the equation

$h=\dfrac{0-(48.60)^2}{-2\times9.8}$

$h=120.50\ m$

The total height reached by the rocket is

$h'=s+h$

$h'=525+120.50$

$h'=645.5\ m$

Hence, The maximum height that the rocket reaches is 645.5 m.

4 0

2 years ago

Answer for brainlest and 20 points

Sholpan [36]

Answer:

Second option: High frequency and low amplitude

Explanation:

7 0

2 years ago

BRAINLIEST HERE COME GET IT

vitfil [10]

Oh that would be lovely! Thank you!

6 0

3 years ago

Read 2 more answers

Calculate the wavelength of the electromagentic waves with the given frequencies, and determine the type of electromagnetic radi

ololo11 [35]

To develop this problem we require the concepts related to wavelength and its expression to calculate it.

The wavelength is given by

$\lambda =\frac{c}{f}$

Where,

$c=3*10^8 m/s$ light velocity

f = frequency.

Our values are given by,

$f_1=4.38*10^{14}Hz$

$f_2= 4.14*10^{20}Hz$

$f_3 = 3.24*10^{12}Hz$

Then,

$\lambda_1=\frac{3*10^8}{4.38*10^{14}}= 6.8493*10^{-7}m$ Visible

$\lambda_2=\frac{3*10^8}{4.14*10^{20}}= 7.24*10^{-13}m$ Gamma Ray

$\lambda_3=\frac{3*10^8}{3.24*10^{12}}= 9.259*10^{-5}m$ Infrared

<em>*Note the designation on the type of rays that are, can be found in consulted via On-line or in the optical books referring to the electromagnetic spectrum table with their respective ranges.</em>

5 0

3 years ago