A rocket being thrust upward as the force of the fuel being burned pushes downward is an example of which of Newton's laws?
2 answers:
A rocket being thrust upward as the force of the fuel being burned pushes upward follows the Newton third law on motion.
Further Explanation:
Newton states three laws on motion.
1. The first law expressed as “If a body is in motion remains in motion and in rest remains in rest except an external force is applied on it.”
2. The second law expressed as “The force applied on the object is equal to the change in the momentum of the object per change in the time.”
3. The third law expressed as “If a force applied on the object then equal and opposite force will be applied by the object.”
Concept:
A rocket being thrust upward as the force of the fuel being burned pushes upward follows the Newton third law on motion as when you want to jump on the ground your foot exerts force on the floor downward at that time the equal force exerted by the floor that is opposite in direction on your foot which make you possible to jump.
Similarly the combustion of the rocket's fuel in the presence of the oxygen produces a lot of gasses and that are exhausted through a nozzle this provides a huge amount of force toward the ground that is a huge force is exerted on the ground. According to Newton’s third law the same amount of huge force exerted on the rocket in upward direction that pull the rocket upward in the air continuously which able the rocket to go in the sky.
Learn more:
1. Conservation of momentum brainly.com/question/9484203.
2. Motion under friction brainly.com/question/7031524.
3. Force on refrigerator brainly.com/question/4033012.
Answer Details:
Grade: High school
Subject: Physics
Chapter: Kinematics
Keywords:
Rocket, thrust, upward, fuel burned, pushes, downward, Newton’s law, law of inertia, law of momentum, energy conservation, momentum conservation, force, action, reaction.
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Answer:
Explanation:
Firstly, when you measure the voltage across the battery, you get the emf,
E = 13.0 V
In order to proceed we have to assume that the voltmeter offers no loading effect, which is a valid assumption since it has a very high resistance.
Secondly, the wires must be uniform. So the resistance per unit length is constant (say z). Now, even though the ammeter has very little resistance it cannot be ignored as it must be of comparable value/magnitude when compared to the wires. This is can seen in the two cases when currents were measured. Following Ohm's law and the resistance of a length of wire being proportional to it's length, we should have gotten half the current when measuring with the 40 m wire with respect to the 20 m wire (). But this is not the case.
Let the resistance of the ammeter be r
Hence, using Ohm's law we get the following 2 equations:
.......(1)
......(2)
Substituting the value of r from (2) in (1), we have,
which simplifying gives us, (which is our required solution)
putting the value of z in either (1) or (2) gives us, r = 0.5325