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Leni [432]
3 years ago
9

A jar contains 8 4/9 pounds of jam. If Sam eats 3 2/5 pounds of the jam, how many pounds of jam remains in the jar?

Mathematics
1 answer:
zepelin [54]3 years ago
5 0
\bf 8\frac{4}{9}\implies \cfrac{8\cdot 9+4}{9}\implies \cfrac{76}{9}
\\\\\\
3\frac{2}{5}\implies \cfrac{3\cdot 5+2}{5}\implies \cfrac{17}{5}\\\\
-------------------------------\\\\
\cfrac{76}{9}-\cfrac{17}{5}\impliedby \textit{let's use an LCD of 45}\implies \cfrac{5\cdot 76-9\cdot 17}{45}
\\\\\\
\cfrac{380-153}{45}\implies \cfrac{227}{45}\implies \boxed{5\frac{2}{45}}
\\\\\\
5\frac{2}{45}\implies \cfrac{5\cdot 45+2}{45}\implies \cfrac{227}{45}
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1)\quad f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

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3) R: y = [0, 384]

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<u>Step-by-step explanation:</u>

Eric's regular wage is $12 per hour for all hours less than 9 hours.

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f(x) = 12x    for   0 ≤ x < 9

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The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).

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f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

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The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.

D:  0 ≤ x ≤ 24        →        D: x = [0, 24]

3) Range represents the y-values (wage Eric will earn).

Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.

The minimum hours he can work in one day is 0.

f(x) = 12x

f(0) = 12(0)

     =  0

The maximum hours he can work in one day is 24 <em>(although unlikely, it is theoretically possible).</em>

f(x) = 18x - 48

f(24) = 18(24) - 48

       = 432 - 48

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D:  0 ≤ y ≤ 384        →        D: x = [0, 384]

4) see graph.

Notice that there is an open dot at x = 9 for f(x) = 12x

and a closed dot at x = 9 for f(x) = 18x - 48

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