Answer:
<h2>n = - 8</h2>
Step-by-step explanation:
![4(n + 5) = 4 + 2n](https://tex.z-dn.net/?f=4%28n%20%2B%205%29%20%3D%204%20%2B%202n)
<u>Expand the terms in the bracket</u>
That's
![4n + 20 = 4 + 2n](https://tex.z-dn.net/?f=4n%20%2B%2020%20%3D%204%20%2B%202n)
Subtract 2n from both sides of the equation
![4n - 2n + 20 = 4 + 2n - 2n \\ 2n + 20 = 4](https://tex.z-dn.net/?f=4n%20-%202n%20%2B%2020%20%3D%204%20%2B%202n%20-%202n%20%5C%5C%202n%20%2B%2020%20%3D%204)
Subtract 20 from both sides of the equation
![2n + 20 - 20 = 4 - 20 \\ 2n = - 16](https://tex.z-dn.net/?f=2n%20%2B%2020%20-%2020%20%3D%204%20-%2020%20%5C%5C%202n%20%3D%20%20-%2016)
<u>Divide both sides by 2</u>
![\frac{2n}{2} = - \frac{ 16}{2} \\](https://tex.z-dn.net/?f=%20%5Cfrac%7B2n%7D%7B2%7D%20%20%3D%20%20-%20%20%5Cfrac%7B%2016%7D%7B2%7D%20%20%5C%5C%20)
We have the final answer as
<h3>n = - 8</h3>
Hope this helps you
The maximum height the ball achieves before landing is 682.276 meters at t = 0.
<h3>What are maxima and minima?</h3>
Maxima and minima of a function are the extreme within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.
We have a function:
h(t) = -4.9t² + 682.276
Which represents the ball's height h at time t seconds.
To find the maximum height first find the first derivative of the function and equate it to zero
h'(t) = -9.8t = 0
t = 0
Find second derivative:
h''(t) = -9.8
At t = 0; h''(0) < 0 which means at t = 0 the function will be maximum.
Maximum height at t = 0:
h(0) = 682.276 meters
Thus, the maximum height the ball achieves before landing is 682.276 meters at t = 0.
Learn more about the maxima and minima here:
brainly.com/question/6422517
#SPJ1
Answer:
IDK but i think the correct answer is (D)
Step-by-step explanation:
Answer:
9) x = 6,4
10) R = -3,-4
Step-by-step explanation:
Hope this helps dude