I: x-2y>=8
II:2x+y<=3
start by isolating y on a side
with I:
x-2y>=8
-2y>=8-x
2y<=x-8
y<=x/2-4
with II:
2x+y<=3
y<=-2x+3
now you can draw I' and II' and read of the solutions with the graph.
transform the inequalities into lines in slope intercept form by replacing the inequality with equality:
y<=x/2-4
->
y=x/2-4
y<=-2x+3
->
y=-2x+3
look at the inequalities to figure out if the area above or below is valid for each line (y<=... -> area below is valid->colored in the attached image)
the area in which all areas overlap is the solution space.
Answer:
The relation
or y = seven-halves x is a direct variation that contains the ordered pair (2,7).
Step-by-step explanation:
Given:
The ordered pair = (2, 7).
Now, to get the direct variation:
As (2,7) lies on it.
So, direct variation means 


Now,




Now, to get the direct variation:


or y = seven-halves x.
Therefore, the relation
or y = seven-halves x is a direct variation that contains the ordered pair (2,7).
No it’s is not greater because 1.8x10-4= 14 and 7.2x10-1=71
5.
that is square-kite
square=AC^2=(AE+EC)^2=(9+15)^2=24^2=576
kite=1/2 times diagonals=1/2 times AC times BD=1/2 times 24 times (BE+ED)=12 times (7+7)=12 times 14=168
so the shaded area=576-168=408 square inches
6.
trapezoid=(base1+base2) times 1/2 times height
big one is base1=14, base2=25
height =10+12=22
area=(1/2)(14+24)(22)=(11)(38)=418
small one is base1=8
base2=25
height is 10
area=(1/2)(25+10)(10)=(5)(35)=175
so shaded area is 418-175=243 square cm
5 and 1 multiply to 5 and add to 6