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kompoz [17]
3 years ago
13

Describe and correct the error Algebra 1 13 POINTS

Mathematics
1 answer:
Elenna [48]3 years ago
7 0

Answer:

im to late lol

Step-by-step explanation:

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Solve Q²= a(p²-b²)/p in form of y=mx+c
umka2103 [35]

Answer:

We want to rewrite:

q^2 = a*(p^2 - b^2)/p

as a linear equation, in the form:

y = m*x + c

So we start with:

q^2 = a*(p^2 - b^2)/p

we can expand the left side to get:

q^2 = (a/p)*p^2 - (a/p)*b^2

q^2 = a*p - (a/p)*b^2

Now we can ust define:

a*p = c

Then we can replace that to get:

q^2 = -(a/p)*b^2 + c

now we can replace:

q^2 = y

b^2 = x

Replacing these, we get:

y = -(a/p)*x + c

finally, we can replace:

-(a/p) = m

then we got the equation:

y = m*x + c

where:

y = q^2

x = b^2

c = a*p

m = -(a/p)

4 0
3 years ago
HELP ASAP!!!!!!!!!!!!!!!!
Contact [7]
<span>The correct answer is: Option (A) </span>\frac{v-z}{w-x}<span>
 
Explanation:
If both lines are parallel, then their slopes must be equal.
 
For the line PQ, the slope is:
Slope of PQ = </span>\frac{v-z}{w-x} --- (1)
 
For the line P'Q', the slope is:
Slope of P'Q' = \frac{v+b-z-b}{w+a-x-a} 
Slope of P'Q' = \frac{v-z}{w-x} --- (2)
 
As (1) = (2), hence the lines are parallel and their slope is \frac{v-z}{w-x} (Option A).
4 0
4 years ago
Read 2 more answers
I need help pleaseeee!!!!! I don’t understand
olganol [36]

Answer:

a. x = 5, m∠FGH = 22°

b. m∠HGI = 22°

c.  m∠FGI = 44°

Step-by-step explanation:

Since GH bisects FGI this means it divides the angle in two equal parts.

a. solving for x means equating them:

5x-3 = 6x-8 =>

5x - 6x = 3 - 8 =>

x = 5.

Both m∠FGH and m∠HGI are 5*5-3 = 22°

c. Add both angles: m∠FGH + m∠HGI = 44°

8 0
3 years ago
6. 2A and ZB are complementary angles. The measure of ZB is (4x), and the
Yakvenalex [24]

Answer:

x = 10°

Step-by-step explanation:

ZA + ZB = 90°

50° + 4x = 90°

4x = 90° - 50°

4x = 40°

x = 10°

6 0
3 years ago
I don't understand this please help
aleksklad [387]
<span>Anna learns in her science class that the human eye blinks an average of 4,200,000 times a year. What is this number expressed in scientific notation?</span>
3 0
3 years ago
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