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diamong [38]
3 years ago
14

A +0.0129 C charge feels a 4110 N

Physics
1 answer:
Otrada [13]3 years ago
6 0

Answer:

r = 14.13 m

Explanation:

Given that,

Charge 1 = +0.0129 C

Charge 2 = -0.00707 C

The force between charges, F = 4110 N

We need to find the distance between charges. Let the distance be r. The force between two charges is given by :

F=\dfrac{kq_1q_2}{r^2}\\\\4110=\dfrac{9\times 10^9\times 0.0129\times 0.00707}{r^2}\\\\r=\sqrt{\dfrac{9\times 10^9\times 0.0129\times 0.00707}{4110}} \\\\r=14.13\ m

So, the distance between charges is equal to 14.13 m.

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