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Ahat [919]
3 years ago
9

What would the answer be for this equation 7x/20 - 5x/12

Mathematics
1 answer:
hodyreva [135]3 years ago
4 0

Answer:

\frac{1}{15} x

Step-by-step explanation:

\frac{7x}{20}  -  \frac{5x}{12}

\frac{3 \times 7x}{3 \times 20}  -  \frac{5 \times 5x}{5 \times 12}

\frac{21x}{60}  -  \frac{25x}{60}

\frac{21x - 25x}{60}  = (21 - 25)x =  - 4x

\frac{ - 4x}{60}  =  -  \frac{ x}{15}

\boxed{\green{=  \frac{1}{15} x}}

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Mathematically verify the outlier(s) in the data set using the 1.5 rule.
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Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

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