See the attached figure to better understand the problem
we know that
tan 29°=AC/CB--------> CB=AC/tan 29°
AC=110 ft
CB--------> <span>how far the man is from the helicopter landing pad
</span>so
CB=AC/tan 29°----------> CB=110/ tan 29°----------> CB=198.45 ft
the answer is
the man is 198.45 ft from the helicopter landing pad
Answer:
option 3
Step-by-step explanation:
V= πr²h
to make h the subject
h= V÷πr²
just take πr² to the other side
as it in multiplication on the left hand side, it will in division in right hand side.
hope it helps!
Multiply 23.93 by 14. There’s the answer
A - The trip was 2 hours and 15 minutes which is also 135 minutes.
B - if the delays occurred the actual arrival time would be 11:15
Hope this helps !
Answer:
C
Step-by-step explanation:
For any given function, all first input values (x-values/coordinates) in the relation are considered as the domain values. While the output values (y-values/coordinates) make up the range of the given function.
The mapped relation that has a domain of {1,2,3}, is the mapped relation that has 1, 2, and 3 on the input side on our left.
Therefore, the mapped relation in option C is the answer.