Question

At what voltage can a 10 μF capacitor be energized to 0.45 J?

Answer 1

Given :

Capacity of capacitor is, $C = 10\ \mu F$.

To Find :

At what voltage can a 10 μF capacitor be energized to 0.45 J.

Solution :

We know, energy in capacitor is given by :

$E = \dfrac{CV^2}{2}$

So,

$V = \sqrt{\dfrac{2E}{C}}\\\\V = \sqrt{\dfrac{2\times 0.45}{10}}\ \mu V\\\\V = 0.3 \ \mu V$

Therefore, voltage required is $0.3 \ \mu V$ .