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3 years ago

What type of energy is formed when chemical bonds are broken?

Physics

1 answer:

torisob [31]3 years ago

8 0

A. Chemical energy is formed when chemical bonds are broken.

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Which travels at a greater speed, visible or infrared light?

Ksju [112]

Infrared light because it is barely able to be seen

7 0

3 years ago

A plane is flying due west at 34 m/s. It encounters a wind blowing at 19 m/s south. Find the resultant veloci

Drupady [299]

Answer:

<em>The resultant velocity has a magnitude of 38.95 m/s</em>

Explanation:

<u>Vector Addition</u>

Given two vectors defined as:

$\vec v_1=(x_1,y_1)$

$\vec v_2=(x_2,y_2)$

The sum of the vectors is:

$\vec v=(x_1+x_2,y_1+y_2)$

The magnitude of a vector can be calculated by

$d=\sqrt{x^2+y^2}$

Where x and y are the rectangular components of the vector.

We have a plane flying due west at 34 m/s. Its velocity vector is:

$\vec v_1=(-34,0)$

The wind blows at 19 m/s south, thus:

$\vec v_2=(0,-19)$

The sum of both velocities gives the resultant velocity:

$\vec v =(-34,-19)$

The magnitude of this velocity is:

$d=\sqrt{(-34)^2+(-19)^2}$

$d=\sqrt{1156+361}=\sqrt{1517}$

d = 38.95 m/s

The resultant velocity has a magnitude of 38.95 m/s

3 0

3 years ago

A marble, a bowling ball, a basketball, and a baseball are all sitting on the top shelf of a display case. Which one has the gre

Katena32 [7]

Answer:

Bowling Ball

Explanation:

The potential energy depends on the factors: mass of the object and distance between the two objects. In this case the distance is between the ground and the balls. Here, the bowling ball is heaviest and its center of mass is farthest in comparison to other two balls. Thus, it has the greatest potential energy.

5 0

3 years ago

A 2400-kg satellite is in a circular orbitaround a planet. The

Fofino [41]

Answer

given,

mass of satellite = 2400 Kg

speed of the satellite = 6.67 x 10³ m/s

acceleration of satellite = ?

gravitational force of the satellite will be equal to the centripetal force

$F = \dfrac{mv^2}{r}$

$F = \dfrac{2400\times (6.67\times 10^3)^2}{r}$

Assuming the radius of circular orbit = 8.92 x 10⁶ m

now,

$F = \dfrac{2400\times (6.67\times 10^3)^2}{8.92\times 10^6}$

F = 11970.11 N

acceleration,

$a = \dfrac{F}{m}$

$a = \dfrac{11970.11}{2400}$

a = 4.98 m/s²

4 0

3 years ago

A 1.0-kilogram ball is dropped from the roof of a building 40. meters tall. What is the approximate time of fall? [Neglect air r

Effectus [21]

H = 40 m, the height from which the ball is dropped.
m = 1 kg, the mass of the ball

Assume g = 9.8 m/s² and neglect air resistance.

The initial vertical velocity is zero.
If t = the time of flight, then
40 m = (1/2)*g*(t s)² = 0.5*9.8*t²
t² = 40/4.9 = 8.1633
t = 2.857 s

Answer: 2.9 s (nearest tenth)

3 0

4 years ago

Read 2 more answers