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Stella [2.4K]
3 years ago
13

GEOMETRY If one point is located at (–6, 2) and another point is located at (6, –3), find the distance between the points.

Mathematics
1 answer:
notka56 [123]3 years ago
7 0

Answer:

It should be 13 units.

Step-by-step explanation:

In the picture shown, the two red dots are the coordinates (-6, 2) and (6, -3). The smaller light blue dots is the distance from one red dot to the other red dot. I counted  17 units between the two and using a ruler, I  estimated 12 units. In conclusion, it should be roughly 13 units. I hope this helps! If this is not the right answer, I would love to recieve some feedback of what I did wrong! Thank you!

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Which of the following is an odd function
nika2105 [10]

Given the functions

(a) f(x) = x³ + 5x² + x

(b) f(x) = x² + x

(c) f(x) = -x

Function (a)

f(-x) = (-x)³ + 5(-x)² + (-x)  

      = -x³ + 5x² - x

      = -(x³ - 5x² + x)

The function is neither even nor odd.

Function (b)

f(-x) = (-x)² + (-x)

       = -(-x² + x)

The function is neither even nor odd.

Function (c)

f(-x) = -(-x)  

      = x

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Because f(-x) = -f(x) the function is odd.

Answer: f(x) = -x is an odd function.

5 0
3 years ago
Please help me <br> Show your work <br> 10 points
Svet_ta [14]
<h2>Answer</h2>

After the dilation \frac{5}{3} around the center of dilation (2, -2), our triangle will have coordinates:

R'=(2,3)

S'=(2,-2)

T'=(-3,-2)

<h2>Explanation</h2>

First, we are going to translate the center of dilation to the origin. Since the center of dilation is (2, -2) we need to move two units to the left (-2) and two units up (2) to get to the origin. Therefore, our first partial rule will be:

(x,y)→(x-2, y+2)

Next, we are going to perform our dilation, so we are going to multiply our resulting point by the dilation factor \frac{5}{3}. Therefore our second partial rule will be:

(x,y)→\frac{5}{3} (x-2,y+2)

(x,y)→(\frac{5}{3} x-\frac{10}{3} ,\frac{5}{3} y+\frac{10}{3} )

Now, the only thing left to create our actual rule is going back from the origin to the original center of dilation, so we need to move two units to the right (2) and two units down (-2)

(x,y)→(\frac{5}{3} x-\frac{10}{3}+2,\frac{5}{3} y+\frac{10}{3}-2)

(x,y)→(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

Now that we have our rule, we just need to apply it to each point of our triangle to perform the required dilation:

R=(2,1)

R'=(\frac{5}{3} x-\frac{4}{3} ,\frac{5}{3}y+ \frac{4}{3})

R'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(1)+ \frac{4}{3})

R'=(\frac{10}{3} -\frac{4}{3} ,\frac{5}{3}+ \frac{4}{3})

R'=(2,3)

S=(2,-2)

S'=(\frac{5}{3} (2)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

S'=(\frac{10}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

S'=(2,-2)

T=(-1,-2)

T'=(\frac{5}{3} (-1)-\frac{4}{3} ,\frac{5}{3}(-2)+ \frac{4}{3})

T'=(-\frac{5}{3} -\frac{4}{3} ,-\frac{10}{3}+ \frac{4}{3})

T'=(-3,-2)

Now we can finally draw our triangle:

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