Refer to the figure given below while reading the solution.
Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.
And then position B when traveled 5 m towards the right turning 90°.
We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).
Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).
Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.
- The shortest distance of B from PQ = AC-AD
- The shortest distance of B from SR = 44-(AC-AD)
- The shortest distance of B from SP = AC+AD
- The shortest distance of B from RQ = 44-(AC+AD)
So, the average of the shortest distances of B from each side is 
Hence, the average of the shortest distance of B from each side is 22 m
Learn more about average here-
brainly.com/question/24057012
#SPJ10
Put your problem in this https://www.cymath.com/ its awesome at solving x
Answer:
(0, 4 )
Step-by-step explanation:
To find the x- intercept, let y = 0 in the equation and solve for x, that is
7x - 4(0) = 28, that is
7x = 28 ( divide both sides by 7 )
x = 4 ← x- intercept ⇒ (0, 4 ) as an ordered pair
Answer:
- 8c - 9c4 d2 - 8c - 9c is a polynomial of type binomial and has a degree 6.