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Law Incorporation [45]
3 years ago
14

Evaluate the expression a-b/c*d when a=48, b=18, c=3, and d=2

Mathematics
1 answer:
barxatty [35]3 years ago
4 0

\huge{\boxed{36}}

Substitute the values. 48 - 18 \div 3 * 2

Follow PEMDAS and multiply and divide first. 48 - 6 * 2

48 - 12

Continue following PEMDAS and subtract. \boxed{36}

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Vitek1552 [10]
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6 0
2 years ago
In the figure below, m2 1=(x-12)° and mZ2 =5xº.<br> Find the angle measures.
erma4kov [3.2K]

Answer:

15 165

Step-by-step explanation:

m1 + m2 = 180

x-18 +5x = 180

6x = 198

x = 33

m1 = 15

m2 = 165

6 0
2 years ago
Consider the parabola r​(t)equalsleft angle at squared plus 1 comma t right angle​, for minusinfinityless thantless thaninfinity
kodGreya [7K]

Given:-   r(t)=< at^2+1,t>  ; -\infty < t< \infty , where a is any positive real number.

Consider the helix parabolic equation :  

                                              r(t)=< at^2+1,t>

now, take the derivatives we get;

                                            r{}'(t)=

As, we know that two vectors are orthogonal if their dot product is zero.

Here,  r(t) and r{}'(t)  are orthogonal i.e,   r\cdot r{}'=0

Therefore, we have ,

                                  < at^2+1,t>\cdot < 2at,1>=0

< at^2+1,t>\cdot < 2at,1>=

                                              =2a^2t^3+2at+t

2a^2t^3+2at+t=0

take t common in above equation we get,

t\cdot \left (2a^2t^2+2a+1\right )=0

⇒t=0 or 2a^2t^2+2a+1=0

To find the solution for t;

take 2a^2t^2+2a+1=0

The numberD = b^2 -4ac determined from the coefficients of the equation ax^2 + bx + c = 0.

The determinant D=0-4(2a^2)(2a+1)=-8a^2\cdot(2a+1)

Since, for any positive value of a determinant is negative.

Therefore, there is no solution.

The only solution, we have t=0.

Hence, we have only one points on the parabola  r(t)=< at^2+1,t> i.e <1,0>




                                               




6 0
3 years ago
FInd the equation of a perpendicular line to y=-2 that passes through the points (4,-2)
Vedmedyk [2.9K]

Answer:

x = 4

Step-by-step explanation:

y=-2 is a horizontal line so x must be a vertical line through (4,-2)

3 0
3 years ago
6x+5y+2z=41<br> 4x-10z=-10<br> -x-2y+2z=-1
Rasek [7]
\left[x \right] = \left[ \frac{5\,y}{158}+\frac{6\,z}{79}\right][x]=[​158​​5y​​+​79​​6z​​]
3 0
3 years ago
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