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2 years ago

I need help im not ready for avid

Mathematics

1 answer:

Mars2501 [29]2 years ago

7 0

Answer:

avid is trash dont join it stop making the same mistakes bro this aint it

Step-by-step explanation:

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Yessirrr help plsllllllllllllssss

neonofarm [45]

Answer:

She earned $7.6

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

To celebrate her birthday, Whitney wants to take her friends adventuring in a 4WD vehicle from All Terrain Tours.

IgorC [24]

Answer:

Whitney can bring 6 friends.

Step-by-step explanation:

The reason why is this:

Whitney is bringing 400 pounds of things plus her own body weight!

400 + 165 = 565 pounds

Now we add on Whitneys freinds which is 165 (their body weight) + the 10 pounds of gear which equals 175 pounds. So each friend would be 175 pounds total weight.

175 x 6 = 1,050 pounds

If we add on Whitneys total weight thats:

565 + 1,050 = 1,615

Adding on another friend would be 1,790 pounds which would be over the weight limit for the vehicle.

Hence, Whitney can bring along 6 friends for her birthday.

Hope this helped! :)

4 0

2 years ago

The perimeter of a triangular field is 120m. Two of the sides are 21m and 40m.Calculate the largest angle of the field.

Mama L [17]

Answer:

the largest angle of the field is 149⁰

Step-by-step explanation:

Given;

perimeter of the triangular filed, P = 120 m

length of two known sides, a and b = 21 m and 40 m respectively

The length of the third side is calculated as follows;

a + b + c = P

21 m + 40 m + c = 120 m

61 m + c = 120 m

c = 120 m - 61 m

c = 59 m

↓ ↓

A → → → → → → → → → → → C

Consider ABC as the triangular field;

Angle A is calculated by applying cosine rule;

$a^2 = b^2 + c^2 - 2bc \ Cos A\\\\Cos \ A = \frac{b^2 + c^2 - a^2}{2bc} \\\\Cos \ A = \frac{40^2 + 59^2 - 21^2}{2 \times 40 \times 59} \\\\Cos \ A = 0.983\\\\A = Cos ^{-1} (0.983)\\\\A = 10.6 \ ^0$

Angle B is calculated as follows;

$Cos \ B = \frac{a^2 + c^2 - b^2}{2ac} \\\\Cos \ B = \frac{21^2 + 59^2 - 40^2}{2 \times 21 \times 59} \\\\Cos \ B = 0.937\\\\B= Cos ^{-1} (0.937)\\\\B = 20.5 \ ^0$

Angle C is calculated as follows;

$Cos \ C = \frac{a^2 + b^2 - c^2}{2ab} \\\\Cos \ C = \frac{21^2 + 40^2 - 59^2}{2 \times 21 \times 40} \\\\Cos \ C = -0.857\\\\C = Cos ^{-1} (-0.857)\\\\C = 149\ ^0$