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3 years ago

I need help im not ready for avid

Mathematics

1 answer:

Mars2501 [29]3 years ago

7 0

Answer:

avid is trash dont join it stop making the same mistakes bro this aint it

Step-by-step explanation:

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I NEED HELP NOW PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! im gonna fail i swear help please now

Tatiana [17]

Answer:

2+2 = 4

Step-by-step explanation:

ok so if u put 2 fingers up and you add 2 more, you get 4

bruv

6 0

3 years ago

Read 2 more answers

Y=6(x-7)(x+2) standard form

STALIN [3.7K]

Answer:

y=6x^2-30x-84

Step-by-step explanation:

3 0

3 years ago

A line of best fit is drawn for the set of points shown on the graph. Which point is an approximate extrapolation for x = 30 fro

Goshia [24]

Answer with explanation:

Equation of Linear Regression line is

y=1.14 x + 3.805

A line of regression is that line which passes through none of the points, few points or all the points in the two dimensional coordinate plane.It tells value of one variable when another variable is known.

for, x=30

y=1.14 × 30 +3.805

y=34.20 +3.805

y=38.005

y=38 (approx)

So, Ordered pair is , (30,38)

Option B

8 0

3 years ago

Read 2 more answers

Somebody please work this out for me

Rashid [163]

The answer is A. -29/8

4 0

4 years ago

What is the area of a regular hexagon with a distance from its center to a vertex of 1 cm? (Hint: A regular hexagon can be divid

devlian [24]

<h3>Answer:</h3><h3>Exact area = $\frac{3}{2}\sqrt{3}$ square cm</h3><h3>Approximate area = 2.598 square cm</h3>

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Work Shown:

s = side length of equilateral triangle = 1 cm

A = area of equilateral triangle with side length 's'

$A = \frac{\sqrt{3}}{4}*s^2$

$A = \frac{\sqrt{3}}{4}*1^2$

$A = \frac{\sqrt{3}}{4}$

This is just one of the 6 equilateral triangles (see diagram below)

Multiply by 6 to get the area of all 6 equilateral triangles, or the entire hexagonal area

$6*A = 6*\frac{\sqrt{3}}{4}$

$6A = \frac{3\sqrt{3}}{2}$

$6A \approx 2.598$

4 0

3 years ago