let's recall that in a Kite the diagonals meet each other at 90° angles, Check the picture below, so we're looking for the equation of a line that's perpendicular to BD and that passes through (-1 , 3).
keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of BD
so we're really looking for the equation of a line whose slope is -1/3 and passes through point A
Answer:
D
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Calculate the slope of the given line using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (- 2, - 4) and (x₂, y₂ ) = (2, 2) ← 2 points on the line
m = =
=
Parallel lines have equal slopes and using (a, b) = (- 3, 1), then
y - 1 = (x - (- 3)), that is
y - 1 = (x + 3) ← in point- slope form