Triangle inequality proof /a + b/ ≤ /a/ + /b/

Mathematics

1 answer:

True [87]3 years ago

4 0

Answer:

a^2+b^2+2|a||b|≥a2+b2+2ab(|a|+|b|)2≥|a+b|2(∵∀x∈R;x2=|x|2)∴|a|+|b|≥|a+b|\

Step-by-step explanation:

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