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2 years ago

The solution set for 7q2 − 28 = 0 is (Separate the solutions with a comma)

Mathematics

2 answers:

professor190 [17]2 years ago

6 0

Answer:

Solution set for the equation is {2, (-2)}.

Step-by-step explanation:

The given equation is 7q² - 28 = 0

Now we add 28 on both the sides of the equation.

7q² - 28 + 28 = 0 + 28

7q² = 28

divide the equation by 7,

$\frac{7q^{2} }{7}=\frac{28}{7}$

$q^{2}=4$

$\sqrt{q^{2}}$ = ± $\sqrt{4}$

q = ± 2

Or q = 2, (-2)

Solution set for the equation is {2, (-2)}.

SCORPION-xisa [38]2 years ago

4 0

7q^2 − 28 = 0
7q^2 = 28
q^2 = 28/7
q^2 = 4
q^2= 2^2
q=+ 2 and q = -2
hope that helps

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The error made by zacharias in solving the quadratic equation 0 = -2x² + 5x - 3 using quadratic formula is; the 2 in the numerator should be –2.

<h3>Quadratic equation</h3>

There are four methods of solving quadratic equation. Namely;

Factorization method
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Step-by-step explanation:

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The common ratio can be found by dividing a term by previous term.

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