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Naddika [18.5K]
3 years ago
11

The solution set for 7q2 − 28 = 0 is (Separate the solutions with a comma)

Mathematics
2 answers:
professor190 [17]3 years ago
6 0

Answer:

Solution set for the equation is {2, (-2)}.

Step-by-step explanation:

The given equation is 7q² - 28 = 0

Now we add 28 on both the sides of the equation.

7q² - 28 + 28 = 0 + 28

7q² = 28

divide the equation by 7,

\frac{7q^{2} }{7}=\frac{28}{7}

q^{2}=4

\sqrt{q^{2}} = ±\sqrt{4}

q = ± 2

Or q = 2, (-2)

Solution set for the equation is {2, (-2)}.

SCORPION-xisa [38]3 years ago
4 0
<span>7q^2 − 28 = 0
</span>7q^2<span> = 28
</span>q^2<span> = 28/7
</span>q^2<span> = 4
</span>q^2= 2^2
<span>q=+ 2 and q = -2 
hope that helps

</span>
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