Answer:
6 3/4 (six and three fourths)
Step-by-step explanation:
First, we must turn 4 6/7 into an improper fraction, AKA 28/7. Now, you can't subtract 1/4 from 28/7, can you? So what you need to do is find the greatest common factor of 4 and 7. The GCF would be 28 (7 x 4 = 28, 4 x 7 = 28).
Now we know that the GCF is 28, we can turn the numbers into 28/28 and 1/28. But wait! We aren't done yet. Now we have to change the numerators. Since you multiplied the denominator (7) by 4 to get 28, you must now multiply 28 by 4 as well. (If you do something to the bottom, you have to do it to the top!) Because of this, we are now at 196/28.
Next, we must do the numerator of 1/28. Since we multiplied the denominator (4) by 7 to get 28, we must now multiply 1 by 7. This gets you to 7/28.
It's finally time to subtract. 196 - 7 is 184, so we are at 184/28. But hey, that's an improper fraction! You have to simplify. 184 divided by 28 is 6.75. 0.75 is 3/4 when turned into a fraction.
Mash 6 and 3/4 together, and you've got your answer! 6 3/4.
Answer:
p = (0.5 , 5)
Step-by-step explanation:
D(-6 ,4) E(7 ,6)
For the line FP to be a median, the point p must have the intermediate value at x and at y between points D and E
p = (Dx + Ex)/2 , (Dy + Ey)/2
p = (-6 + 7)/2 , (4 + 6)/2
p = 1/2 , 10/2
p = (0.5 , 5)
This is because for a medium to be the point p has to be right in the middle of the other 2 vertices
Answer:
Where is the question?
Step-by-step explanation:
please attach it...
Answer:
x = -0.6
y = 2.2
z = 2
Step-by-step explanation:
2x + y - 2z = -3
x + 3y - z = 4
3x + 4y - z = 5
Rewrite the system in matrix form and solve it by Gaussian Elimination (Gauss-Jordan elimination)
2 1 -2 -3
1 3 -1 4
3 4 -1 5
R1 / 2 → R1 (divide the 1 row by 2)
1 0.5 -1 -1.5
1 3 -1 4
3 4 -1 5
R2 - 1 R1 → R2 (multiply 1 row by 1 and subtract it from 2 row); R3 - 3 R1 → R3 (multiply 1 row by 3 and subtract it from 3 row)
1 0.5 -1 -1.5
0 2.5 0 5.5
0 2.5 2 9.5
R2 / 2.5 → R2 (divide the 2 row by 2.5)
1 0.5 -1 -1.5
0 1 0 2.2
0 2.5 2 9.5
R1 - 0.5 R2 → R1 (multiply 2 row by 0.5 and subtract it from 1 row); R3 - 2.5 R2 → R3 (multiply 2 row by 2.5 and subtract it from 3 row)
1 0 -1 -2.6
0 1 0 2.2
0 0 2 4
R3 / 2 → R3 (divide the 3 row by 2)
1 0 -1 -2.6
0 1 0 2.2
0 0 1 2
R1 + 1 R3 → R1 (multiply 3 row by 1 and add it to 1 row)
1 0 0 -0.6
0 1 0 2.2
0 0 1 2
x = -0.6
y = 2.2
z = 2
1.04 kilograms
1 gram = .001 kilogram
2x520= 1040
1040 x .001 = 1.04 kilograms
