X^4-3x³+4x
x^4-3x³+3x+x
(x^4+x)-(3x³-3x)
x(x³+1)-3x(x²-1)
x(x+1)(x²-x+1)-3x(x+1)(x-1)
x(x+1)(x²-x+1-3x+3)
x(x+1)(x²-4x+4)
x(x+1)(x-2)(x-2)
so x intercepts are (0,0), (-1,0) and (2,0)
the y intercept is (0,0)
Answer:
16
Step-by-step explanation:
To solve a quadratic equation by using the completing the square method, the coefficient of the square term i.e x² must be one (1).
Therefore, we would have to first make the coefficient of x² to be equal to 1.
4x² + 24x + 8 = 32
We would simplify the equation;
4x² + 24x = 32 - 8
4x² + 24x = 24
Divide all through by 4;
x² + 8x = 24
The value to be added = (8/2)² = 4² = 16
x² + 8x + 16 = 8 + 16
x² + 4x + 4x + 16 = 24
x(x + 4) + 4(x + 4) = 24
(x + 4)² = 24
Taking the square root of both sides;
x + 4 = ± 4.9
x = -4 ± 4.9
x = -4 + 4.9 = 0.9
or
x = -4 - 4.9 = - 8.9
<em>Therefore, 16 must be added to solve the quadratic equation by completing the square method. </em>
Answer:
Answer to the question:
Step-by-step explanation:
α= 54º
V= 66 ft/s
g= 9.8 m/s²
Vx= V * cos(54º) = 38.8 ft/s
Vy= V * sin(54º) = 53.4 ft/s
<u>PARAMETRIC EQUATIONS:</u>
x(t)= Vx * t
y(t)= Vy * t - (g * t²)/2
Answer:
you answer should be b
Step-by-step explanation:
I am not 100% sure
<u>Answer:</u>
Standard form of a line passing through (-2, 4) and having slope of -1/7 is x + 7y = 26
<u>Solution:</u>
Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7
Standard form of line passing through point ( a , b ) and having slope m is given by
(y – b) = m ( x – a) --------(1)
In our case given point is ( -2 , 4 ) and slope is -1/7 that means
a = -2 , b = 4 , m = -(1/7)
On substituting given value of a , b and m is equation (1) we get


=> 7( y - 4 ) = -x – 2
=> 7y + x = -2 + 28
=> x + 7y = 26
Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26