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aivan3 [116]
4 years ago
13

The balance on a car loan after 4 years is $8,996.32. The interest rate is 5.6% compounding annually. What was the initial value

of the loan?
Mathematics
1 answer:
Slav-nsk [51]4 years ago
6 0
You would get 2015.17568 as the interest rate i believe 
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The current value of a baseball card is 60 times its original value v
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60v = $15

60v/60 = $15/60

v = 0.25

The original value of the baseball card is $0.25
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Four times the difference of b and six is equal to b squared
Tcecarenko [31]

Answer:

4(b-6)=b^2

Step-by-step explanation:

The difference would mean that it is subtraction and you multiply that difference by 4 and set it equal to b squared

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3 years ago
Which expression is equivalent to
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i think the answer is, A...

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HELP ME OUT ASAP PLS 20POINTS IF U DO! On Friday, a bowling alley made $842.72 from lane rentals and $412.38 from the concession
ElenaW [278]

Answer:

  $2611.05

Step-by-step explanation:

  earnings = lane rentals + concessions

<u>Friday</u>:

  earnings = $842.72 +412.38 = $1255.10

<u>Saturday</u>:

We assume "down by 1/8" means the value was 1 -1/8 = 7/8 that of the previous day. Likewise, "increased by 1/2" is assumed to mean the value was 1 + 1/2 = 3/2 that of the previous day.

  earnings = 7/8×$842.72 + 3/2×412.38 = $1355.95

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7 0
3 years ago
Read 2 more answers
The admissions office of a private university released the following data for the preceding academic year: From a pool of 3900 m
Finger [1]

Answer:

a. 0.09 or 9%

b. 0.324 or 32.4%

c. 0.0972 or 9.72%

Step-by-step explanation:

Male applicants = 3900

Female applicants = 3600

Total applicants = 7,500

Proportion of male applicants (m) = 0.52

Proportion of female applicants (f) = 0.48

a. The probability that a random male applicant is accepted and enrolls is given by the probability of a male student being accepted multiplied by the probability of a male student enrolling:

P(a) = 0.30*0.30=0.09=9\%

b. The probability that a random student is accepted is given by the probability of a male applicant being accepted added to the probability of a female applicant being accepted

P(b) = m*0.30+f*0.35\\P(b) = 0.52*0.30+0.48*0.35\\P(b) = 0.324=32.4\%

c. The probability that a random student is accepted and enrolls is given by the probability of a male applicant being accepted and enrolling added to the probability of a female applicant being accepted and enrolling

P(b) = m*0.30*0.30+f*0.35*0.30\\P(b) = 0.52*0.30*0.30+0.48*0.35*0.30\\P(b) = 0.0972=9.72\%

7 0
3 years ago
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