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3 years ago

12

Match the following items on the left with the items on the right by entering the correct letter in the box. Scalene A Obtuse B

Hexagon C Right D Pentagon E Quadrilateral F

1 answer:

Sidana [21]3 years ago

6 0

Answer:

right D

Step-by-step explanation:

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A restaurant operator in Accra has found out that during the partial lockdown, if she sells a plate of her food for GH¢20 each,

Lilit [14]

Answer:

Step-by-step explanation:

First, note this parameters from the question.

We let x = number of $5 increases and number of 10 decreases in plates sold.

Our Revenue equation is:

R(x) = (300-10x)(10+5x)

We expand the above equation into a quadratic equation by multiplying each bracket:

R(x) = 3000 + 1500x - 3000x - 1500x^2

R(x) = -1500x^2 - 1500x + 3000 (collect like terms)

Next we simplify, by dividing through by -1500

= 1500x^2/1500 - 1500x/1500 + 3000/1500

= X^2 - x + 2

X^2 - x + 2 = 0

Next, we find the axis of symmetry using the formula x = -b/(2*a) where b = 1, a = 1

X = - (-1)/2*1

X = 1/2

Number of $5 increases = $5x1/2 = $2.5

=$2.5 + $20 = $22.5 ticket price gives max revenue.

7 0

3 years ago

Find the area of the shaded region. Round to the nearest tenth.

AURORKA [14]

Answer:

3.5 square cm

Step-by-step explanation:

$Area \: of \: both \: squares \\ = {2}^{2} + {3}^{2} \\ = 4 + 9 \\ = 13 \: {cm}^{2} \\ \\ Area \: of \: both \: right \: \triangle s \\ = \frac{1}{2} \times (2 + 3) \times 2 + \frac{1}{2} \times3 \times 3 \\ = 5 \times 1+ 1.5 \times 3 \\ = 5 + 4.5 \\ = 9.5 \: {cm}^{2} \\ \\ Area \: of \:shaded \: region \\ = Area \: of \: both \: squares\\ - Area \: of \: both \: right \: \triangle s \\ = 13 - 9.5 \\ \purple { \boxed{ \bold{Area \: of \:shaded \: region = 3.5 \: {cm}^{2} }}}$

7 0

3 years ago

After the fraction x plus 1 all over 2 minus the fraction x plus 2 all over 3 x have been combined using the least common denomi

RoseWind [281]

If I've read this correctly, it looks like this.

$\dfrac{(x + 1)}{2 - \dfrac{(x + 2)}{3x}}$

If that is correct, then the first step is to put the top part of the denominator over 3x

$\dfrac{(x + 1)}{\dfrac{6x - (x + 2)}{3x}} = \dfrac{(x + 1)}{\dfrac{5x -2}{3x}}$

The next part is to flip a three tier fraction. I'm afraid I have to show what happens. My latex is not that strong.

What you get is

$\dfrac{3x*(x + 1)}{(5x - 2)}$

This is just about your final answer. You could write it as

$\dfrac{3x^2 + 3x}{(5x - 2)}$

6 0

3 years ago

Given: f(x)=x^2, g(x)=x+6, h(x)=7<br><br>Find h{g[f(x)]}

arsen [322]

Step-by-step explanation:

$f(x)=x^2,\ g(x)=x+6,\ h(x)=7\\\\h(x)=7\ \text{It's the constant function. Therefore}\ h\{g[f(x)]\}=7$

4 0

3 years ago

Expand and reduce (2+√3)^2

nasty-shy [4]

Answer:

7 + 4 $\sqrt{3}$

Step-by-step explanation:

note that $\sqrt{a}$ × $\sqrt{a}$ = a

Given

(2 + $\sqrt{3}$ )² = (2 + $\sqrt{3}$ )(2 + $\sqrt{3}$ )

Each term in the second factor is multiplied by each term in the first factor, that is

2(2 + $\sqrt{3}$ ) + $\sqrt{3}$ (2 + $\sqrt{3}$ ) ← distribute both parenthesis

= 4 + 2 $\sqrt{3}$ + 2 $\sqrt{3}$ + 3 ← collect like terms

= 7 + 4 $\sqrt{3}$

6 0

3 years ago