The correct answer is -2
Can you mark me as brainliest?
Answer:
<em><u>The number of students that like only Nokia </u></em>
<h2>= 30</h2>
Step-by-step explanation:
consider N the number of students who like Nokia → N=?
T the number of students who like Techno → T=35
Statement 1: In a class of 40 students, 5 like neither Nokia nor Techno
we can translate it like this: 35 student like Nokia or Techno
we can note it like this : T∪N= 35
Statement 2: 30 like Techno and Nokia
we can note it : T∩N = 30
using a rule concerning the number of element of a set :
T∪N = N + T - T∩N
then
35 = N + 35 - 30
⇒ N - 30 = 0
⇒ N = 30
Answer:
Step-by-step explanation:
<u>a)</u>
- Given that ; X ~ N ( µ = 65 , σ = 4 )
From application of normal distribution ;
- Z = ( X - µ ) / σ, Z = ( 64 - 65 ) / 4, Z = -0.25
- Z = ( 66 - 65 ) / 4, Z = 0.25
Hence, P ( -0.25 < Z < 0.25 ) = P ( 64 < X < 66 ) = P ( Z < 0.25 ) - P ( Z < -0.25 ) P ( 64 < X < 66 ) = 0.5987 - 0.4013
- P ( 64 < X < 66 ) = 0.1974
b) X ~ N ( µ = 65 , σ = 4 )
From normal distribution application ;
- Z = ( X - µ ) / ( σ / √(n)), plugging in the values,
- Z = ( 64 - 65 ) / ( 4 / √(12)) = Z = -0.866
- Z = ( 66 - 65 ) / ( 4 / √(12)) = Z = 0.866
P ( -0.87 < Z < 0.87 )
- P ( 64 < X < 66 ) = P ( Z < 0.87 ) - P ( Z < -0.87 )
- P ( 64 < X < 66 ) = 0.8068 - 0.1932
- P ( 64 < X < 66 ) = 0.6135
c) From the values gotten for (a) and (b), it is indicative that the probability in part (b) is much higher because the standard deviation is smaller for the x distribution.
Answer:
2n
Step-by-step explanation:
I think it might be 2n sorry if I'm wrong
