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3 years ago

Joseph rides his bike for 30 miles in one hour

Chemistry

1 answer:

Anton [14]3 years ago

6 0

Answer:

velocity

Explanation:

because he is going 30 miles west

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Why is radon-222 considered dangerous?

Marysya12 [62]

q1. all of these

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educated guess and i remember some things from chem. Hope its all good

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4 years ago

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Heroin was originally going to be called "wunderlich", a German word for wonderful, since one chemist thought the substance made

Zarrin [17]

Answer:

heroic

Explanation:

Bayer, a German pharmaceutical company, named the substance it synthesized "heroin", probably from the word heroisch, German for heroic, because in field studies people using the medicine felt "heroic".

BTW, I found this information on this wedsite: https://www.answers.com/Q/Where_did_heroin_get_its_name

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3 years ago

Which statement best explains how the solution should be made? Add 49. 6 mL of 0. 250 M sucrose to 400. 0 mL of water to get 400

soldier1979 [14.2K]

The Last one thank you thank you hope this helped!

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3 years ago

How have chemists helped fight leukemia

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4 years ago

Erioglucine is a blue-colored dye that absorbs its complementary color, red, in aqueous solution around 645 nm. Unfortunately, t

ExtremeBDS [4]

Answer:

For the control experiment: $0.0552 M$ of aqueous solution of erioglaucine has absorbance of $0.035 M\\$

From Lambert-Beer's law we know:

$Absorbance = e\cdot c \cdot l\\$

Here; e is the molar absorptivity coefficient of erioglaucine

l = length of cuvette in which the solution is taken = $1 cm$

A sorbance by the erioglaucine = total absorbance - absorbance by distilled $water = 0.331-0.019 = 0.312$

So; by putting the values in the above equation; we get:

$0.312 = 0.0552 M \cdot e\cdot~1cm\\$

So; $e = \frac{0.331}{0.0552} M^{-1}cm^{-1}= 5.65 M^{-1}cm^{-1}$

The molar absorptivity coefficient of erioglaucine is $5.65 M^{-1}cm^{-1}\\$

The absorbance of erioglaucine in distilled water (contaminated with metal ions) is: $0 .217$

The absorbance of distilled water is $0.019$

So; absorbance of erioglaucine itself is : $0.217-0.019 = 0.198$

Again using Lambert Beer law; we get:

$A= e\cdot c\cdot l$

$0.198 = 5.65 M^{-1}cm^{-1} \cdot c \cdot 1 cm$ $( c = concentrartion)$

c = 0.198/5.65 M = 0.035 M

The concentration of the erioglaucine is $0.035 M\\$

Explanation:

4 0

4 years ago