Both of them have high electronegativity. Hence they both tend to gain electrons to gain stability.
The group is might be labeled as VIIB or VIIA.
The process that is an example of a chemical change would be of ice turning into water when heated over a Bunsen Burner.
Answer:
Fe₂(SO₄)₃ + 6KOH —> 3K₂SO₄ + 2Fe(OH)₃
The coefficients are: 1, 6, 3, 2
Explanation:
__Fe₂(SO₄)₃ + __KOH —> __K₂SO₄ + __Fe(OH)₃
To determine the correct coefficients, we shall balance the equation. This can be obtained as follow:
Fe₂(SO₄)₃ + KOH —> K₂SO₄ + Fe(OH)₃
There are 2 atoms of Fe on the left side and 1 atom on the right side. It can be balance by writing 2 before Fe(OH)₃ as shown below:
Fe₂(SO₄)₃ + KOH —> K₂SO₄ + 2Fe(OH)₃
There are 6 atoms of OH on the right side and 1 atom on the left side. It can be balance by writing 6 before KOH as shown below:
Fe₂(SO₄)₃ + 6KOH —> K₂SO₄ + 2Fe(OH)₃
There are 6 atoms of K on the left side and 2 atoms on the right side. It can be balance by writing 3 before K₂SO₄ as shown below:
Fe₂(SO₄)₃ + 6KOH —> 3K₂SO₄ + 2Fe(OH)₃
Now, the equation is balanced.
Therefore, the coefficients are: 1, 6, 3, 2
