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ivanzaharov [21]
1 year ago
9

find the activity coefficient of h , in a solution containing 0.010 m hcl plus 0.040 kclo4. what is the ph of the solution?

Chemistry
1 answer:
Lisa [10]1 year ago
4 0

The activity coefficient of h is 0.05

The ph of the solution is 2.08

To find the activity coefficient, apply the concept of ionic equilibrium

h( activity coefficient)= 1/2CZ²

C is the concentration of species

Z is the charge on individual species

<em>h= 1/2( 0.01 x1²+ 0.04x (-1)²+0.01 x1²+0.04x (-1)²)</em>

<em>h= 0.05 </em>

For the pH of the solution, apply the formula

<em>pH= -log( H⁺x0.83)</em>

<em>pH = - log(0.01x0.83)</em>

<em>= 2.08</em>

To learn more about the pH of the solution, visit brainly.com/question/26767292

#SPJ4

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If volumes are additive and 253 mL of 0.19 M potassium bromide is mixed with 441 mL of a potassium dichromate solution to give a
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Answer:

The concentration of the Potassium Dichromate solution is 0.611 M

Explanation:

First of all, we need to understand that in the final solution we'll have potassium ions coming from KBr and also K2Cr2O7, so we state the dissociation equations of both compounds:

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This is the final quantity of potassium ion moles we have present once we mixed the KBr and K2Cr2O7 solutions. Because we already know the amount of K+ moles that were added with the KBr solution (0.04807 moles), we can calculate the contribution corresponding to K2Cr2O7:

0.587124 final K+ moles - 0.04807 K+ moles from KBr = 0.539054 K+ moles from K2Cr2O7

If we go back and take a look a the chemical reactions, we can see that 1 mole of K2Cr2O7 dissociates into 2 moles of K+ ions, so:

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Now this quantity of potassium dichromate moles came from the respective  solution, that is 441 mL, so we calculate the amount of them that would be present in 1000 mL to determine de molar concentration:

441 mL ----- 0.269527 K2Cr2O7 moles

1000 mL ----- x = 0.6112 K2Cr2O7 moles = 0.6112 M

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