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Greeley [361]
3 years ago
7

You probably already know the names of some molecules. Identify which compound (water, salt, carbon dioxide, or methane) corresp

onds to each of the following chemical formulas. H2O is . CO2 is . NaCl is . CH4 is .
Chemistry
2 answers:
vladimir1956 [14]3 years ago
7 0

CO2 is carbon

H2O is water

CH4 is methane

NaCI is salt

Natali5045456 [20]3 years ago
6 0

Explanation:

Water has a formula which represents two hydrogen atoms are attached to one oxygen atom. Therefore, the formula of water is H_{2}O.

Salt is also known as sodium chloride. Its formula represents that one sodium atom is attached to one chlorine atom, therefore, its formula is NaCl.

Carbon dioxide has a formula which represents one carbon atom is attached to two oxygen atoms. Therefore, its formula is CO_{2}.

Methane has a formula which represents one carbon atom is attached to four hydrogen atoms. Therefore, its formula is CH_{4}.

Thus, we can conclude that H_{2}O is water, CO_{2} is carbon dioxide, NaCl is salt, and CH_{4} is methane.


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Elanso [62]

Answer: IT IS D

Explanation:

8 0
3 years ago
Calculate the volume in milliliters of a iron(II) bromide solution that contains of iron(II) bromide . Round your answer to sign
miv72 [106K]

This is an incomplete question, here is a complete question.

Calculate the volume in milliliters of a 1.29 mol/L iron(II) bromide solution that contains 275 mmol of iron(II) bromide . Round your answer to significant 3 digits.

Answer  : The volume of iron(II) bromide solution is, 2.13\times 10^2mL

Explanation : Given,

Concentration of iron(II) bromide = 1.29 mo/L

Moles of iron(II) bromide = 275 mmol = 0.275 mol

conversion used : 1 mmol = 0.001 mol

Now we have to calculate the volume of iron(II) bromide.

\text{Volume of iron(II) bromide}=\frac{Moles of iron(II) bromide}}{\text{Concentration of iron(II) bromide}}

Now put all the given values in this formula, we get:

\text{Volume of iron(II) bromide}=\frac{0.275mol}{1.29mol/L}=0.213L=2.13\times 10^2mL

Thus, the volume of iron(II) bromide solution is, 2.13\times 10^2mL

5 0
3 years ago
PLEASE HELP ME
Dmitriy789 [7]
Hello!

The ball took up 2,9L

To solve this problem, we should apply the ideal gas law and clear for n (the number of moles), as this value doesn't change when Devin takes the ball to the garage:

n= \frac{P1*V1}{RT1}=\frac{P2*V2}{RT2}

Now, we should clear this equation to find V2, as this is the value we are looking for:

V2= \frac{P1*V1*T2}{P2*T1}= \frac{400kPa*3L*250K}{350kPa*300K}=2,857L≈2,9L

Have a nice day!
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kiruha [24]
My answer -

 
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P.S

Have an AWESOME!!! day :)
8 0
4 years ago
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