Answer:
А.The system has two solutions, but only one is viable because the other results in a negative width.
Step-by-step explanation:
Given
Let:
length of play area A
width of play area A
length of play area B
width of play area B
Area of A
Area of B
From the question, we have the following:




The area of A is:

This gives:

Open bracket

The area of B is:


Substitute: 

Open brackets


Expand


We have that:

This gives:

Collect like terms


Using quadratic calculator, we have:
or
--- approximated
But the width can not be negative; So:

You have to have the same denominator for both fractions, so I would multiply 3/4 by 3 that would give you 9/12 and the other one is 7/12. This means that the final answer would be 9/12>7/12.
Answer is
D
(You are welcome)
Answer:
✔ a/f
✔ cf
✔ c/b
✔ cf + ec
✔ c
Step-by-step explanation:
just did it on edg
Answer:
5
Step-by-step explanation:
Plug x in as 0.
f(x)=0+0+5
f(x)=5