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NikAS [45]
4 years ago
11

Opal is a hydrated form of silica. If a laboratory analysis of a sample of opal reveals it to contain29.2% Si, 33.3%O, and 37.5%

H 22 O, what is its empirical formula?
Chemistry
1 answer:
ZanzabumX [31]4 years ago
8 0
Let us assume that there is a 100g sample of Opal. The masses of each element will be:
29.2g Si
33.3g O
37.5g H2O
Now we divide each constituent's mass by its Mr to get the moles present
Si: (29.2 / 28) = 1.04
O: (33.3 / 16) = 2.08
H2O: (37.5 / 18) = 2.08
Now we divide by the smallest number and obtain:
Si: 1
O: 2
H2O: 2
Thus, the empirical formula of Opal is:
SiO2 . 2H2O
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3. How many atoms are found in 5.20 g of magnesium (Mg)?
Ganezh [65]

Explanation:

In order to go from mass of magnesium to atoms of magnesium, we have to do two things:

   Convert mass of Mg to moles of Mg using the molar mass of Mg as a conversion factor

   Convert moles of Mg to atoms of Mg using Avogadro's number (6.02×1023) as a conversion factor

Step 1:

Before we start, I should note that the molar mass of Mg is 24.31gmol. We can go from mass to moles using dimensional analysis. The key to dimensional analysis is understanding that the units that you don't need any more cancel out, leaving the units that are desired:

48.60g

×1mol24.31g

=2.00mol

Step 2:

We'll use this relationship:

www.sprinklernewz.uswww.sprinklernewz.us

Using the moles of Mg that we just obtained, we can use Avogrado's number to perform dimensional analysis in order to cancel out units of mol to end up with atoms of Mg:

2.00mol

×6.02×1023atoms1mol

=1.204×1024atoms

Thus, 48.60g of Mg is equivalent to 1.204×1024atoms

Hope this helped :)

6 0
3 years ago
On a very small scale, the numbers of particles of each substance in a reaction are represented by the _______ in the balanced c
Svetach [21]
<span>On a very small scale, the numbers of particles of each substance in a reaction are represented by the coefficients in the balanced chemical equation describing the reaction. Hope this answers the question. Have a nice day.</span>
6 0
3 years ago
Approximately how many atoms make up 2.3 moles of gallium
mars1129 [50]
C is the correct answer
3 0
4 years ago
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Calculate the grams of nitrogen in 125 g of NH4NO3
Marta_Voda [28]

Answer:

43.75 g of Nitrogen

Explanation:

We'll begin by calculating the mass of 1 mole of NH₄NO₃. This can be obtained as follow:

Mole of NH₄NO₃ = 1 mole

Molar mass of NH₄NO₃ = 14 + (4×1) + 14 + (3×16)

= 14 + 4 + 14 + 48

= 80 g/mol

Mass of NH₄NO₃ =?

Mass = mole × molar mass

Mass of NH₄NO₃ = 1 × 80 = 80 g

Next, we shall determine the mass of N in 1 mole of NH₄NO₃.

Mass of N in NH₄NO₃ = 2N

= 2 × 14

= 28 g

Thus,

80 g of NH₄NO₃ contains 28 g of N.

Finally, we shall determine the mass of N in 125 g of NH₄NO₃. This can be obtained as follow:

80 g of NH₄NO₃ contains 28 g of N.

Therefore, 125 g of NH₄NO₃ will contain = (125 × 28) / 80 = 43.75 g of N.

Thus, 125 g of NH₄NO₃ contains 43.75 g of Nitrogen

5 0
3 years ago
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Answer:number 2

Explanation:

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